Finance-Theory Β· Unit 16 Β· Video 4 Β· Interactive Practice

How Correlation Bends the Bullet, from +1 to βˆ’1

IKey Formulas

FormulaCaseHow to read it
E[Rp]=Ο‰aΞΌa+Ο‰bΞΌb\text{E}[R_p] = \omega_a\mu_a + \omega_b\mu_bExpected returnNo ρ\rho in it: changing the correlation never moves a portfolio's expected return
Var[Rp]=Ο‰a2Οƒa2+Ο‰b2Οƒb2+2Ο‰aΟ‰bΟƒaΟƒbρab\text{Var}[R_p] = \omega_a^2\sigma_a^2 + \omega_b^2\sigma_b^2 + 2\omega_a\omega_b\sigma_a\sigma_b\rho_{ab}Varianceρ\rho sits only in the cross term; at ρ=0\rho = 0 that term drops out
SD[Rp]=Ο‰aΟƒa+Ο‰bΟƒb\text{SD}[R_p] = \omega_a\sigma_a + \omega_b\sigma_bρ=+1\rho = +1For 0≀ω≀10 \le \omega \le 1 a weighted average of the two SDs: a straight line, no risk reduction
SD[Rp]=βˆ£Ο‰aΟƒaβˆ’Ο‰bΟƒb∣\text{SD}[R_p] = |\omega_a\sigma_a - \omega_b\sigma_b|ρ=βˆ’1\rho = -1Zero when Ο‰aΟƒa=Ο‰bΟƒb\omega_a\sigma_a = \omega_b\sigma_b, at Ο‰b=ΟƒaΟƒa+Οƒb\omega_b = \dfrac{\sigma_a}{\sigma_a + \sigma_b}: two straight segments meeting on the vertical axis

Key Insight: The two stocks' means and standard deviations fix the endpoints, and the correlation decides how far the curve between them bends west. For GM and Motorola the 75/25 mix earns about 1.25%1.25\% a month whatever ρ\rho is, while its risk runs from about 7.1%7.1\% at ρ=+1\rho = +1 down to 2.24%2.24\% at ρ=βˆ’1\rho = -1.

IICorrelation Bends the Bullet

Lowering ρ\rho leaves every portfolio's expected return in place and moves only its risk, bending the curve west.

IIIThe ρ = βˆ’1 Triangle

At ρ=βˆ’1\rho = -1 the weighted SDs subtract, so one mix of two illustrative stocks carries no risk.

πŸ’‘ For the illustrative Ibis–Jacana pair, a riskless 0.97%0.97\% a month, about 11.6%11.6\% a year, far above a T-bill's yield, would be an arbitrage, a free lunch. That is why no real pair of assets has a correlation of exactly βˆ’1-1.

IVQuiz Questions

Problem 1 Β· Risk of an Even Split

Given: two illustrative stocks with monthly figures: Ibis has mean 0.7%0.7\% and standard deviation 4%4\%, Jacana has mean 1.5%1.5\% and standard deviation 8%8\%, and their correlation is ρ=0.5\rho = 0.5. Find the standard deviation of a portfolio with 50%50\% in each.

βœ… Correct! The variance is 4+16+8=284 + 16 + 8 = 28 in %2\%^2, and 28β‰ˆ5.29%\sqrt{28} \approx 5.29\%: less than the 6%6\% average of the two SDs, because ρ<1\rho < 1.
❌ Close, but… the cross term carries a factor of 22: 2(0.5)(0.5)(4)(8)(0.5)=82(0.5)(0.5)(4)(8)(0.5) = 8, not 44. With 44 you get 24β‰ˆ4.90%\sqrt{24} \approx 4.90\%.
❌ Not quite. 0.5Γ—4+0.5Γ—8=60.5 \times 4 + 0.5 \times 8 = 6 is the weighted average of the SDs, which is the portfolio SD only at ρ=+1\rho = +1. At ρ=0.5\rho = 0.5 the cross term is smaller, so the risk is lower.
❌ Not quite. 4+16β‰ˆ4.47%\sqrt{4 + 16} \approx 4.47\% leaves out the cross term, which is right only at ρ=0\rho = 0. Here ρ=0.5\rho = 0.5 adds 88 to the variance.
Show solution

With Ο‰Ibis=Ο‰Jacana=0.5\omega_{\text{Ibis}} = \omega_{\text{Jacana}} = 0.5, variances in %2\%^2:

Var[Rp]=0.52(42)+0.52(82)+2(0.5)(0.5)(4)(8)(0.5)=4+16+8=28\text{Var}[R_p] = 0.5^2(4^2) + 0.5^2(8^2) + 2(0.5)(0.5)(4)(8)(0.5) = 4 + 16 + 8 = 28 SD[Rp]=28β‰ˆ5.29%Β perΒ month\text{SD}[R_p] = \sqrt{28} \approx 5.29\% \text{ per month}

The expected return is 0.5(0.7)+0.5(1.5)=1.1%0.5(0.7) + 0.5(1.5) = 1.1\%, exactly halfway between the stocks, but the risk is below the halfway value of 6%6\%.

Problem 2 Β· What a Lower Correlation Changes

Given: the same illustrative stocks (Ibis 0.7%0.7\% and 4%4\%, Jacana 1.5%1.5\% and 8%8\% per month) and a portfolio with 25%25\% in Ibis and 75%75\% in Jacana. Their correlation falls from ρ=0.5\rho = 0.5 to ρ=βˆ’0.5\rho = -0.5. Which statement describes the change?

βœ… Correct! The portfolio moves straight west: the same 1.30%1.30\% return with about one point less risk.
❌ Not quite. The expected return Ο‰aΞΌa+Ο‰bΞΌb\omega_a\mu_a + \omega_b\mu_b has no ρ\rho in it, so it stays at 1.30%1.30\%. Only the risk moves.
❌ Close, but… those values use a cross term of 6ρ6\rho. The factor of 22 makes it 2(0.25)(0.75)(4)(8)ρ=12ρ2(0.25)(0.75)(4)(8)\rho = 12\rho.
❌ Close, but… 5%=∣0.25Γ—4βˆ’0.75Γ—8∣5\% = |0.25 \times 4 - 0.75 \times 8| is the shortcut that holds only at ρ=βˆ’1\rho = -1. At ρ=βˆ’0.5\rho = -0.5 the variance is 1+36βˆ’6=311 + 36 - 6 = 31.
Show solution

Expected return (no ρ\rho): 0.25(0.7)+0.75(1.5)=0.175+1.125=1.30%0.25(0.7) + 0.75(1.5) = 0.175 + 1.125 = 1.30\% at either correlation.

Variance in %2\%^2, as a function of ρ\rho:

Var[Rp]=0.252(16)+0.752(64)+2(0.25)(0.75)(4)(8)ρ=1+36+12ρ\text{Var}[R_p] = 0.25^2(16) + 0.75^2(64) + 2(0.25)(0.75)(4)(8)\rho = 1 + 36 + 12\rho

At ρ=0.5\rho = 0.5: 37+6=4337 + 6 = 43, so SD=43β‰ˆ6.56%\text{SD} = \sqrt{43} \approx 6.56\%.

At ρ=βˆ’0.5\rho = -0.5: 37βˆ’6=3137 - 6 = 31, so SD=31β‰ˆ5.57%\text{SD} = \sqrt{31} \approx 5.57\%.

The lower correlation sheds about one point of risk at an unchanged return.

Problem 3 Β· Two Mixes with the Same Risk

Given: the illustrative Ibis (0.7%0.7\%, 4%4\%) and Jacana (1.5%1.5\%, 8%8\%) with correlation exactly ρ=βˆ’1\rho = -1, long positions only (0≀ωIbis≀10 \le \omega_{\text{Ibis}} \le 1). Two portfolios have a standard deviation of exactly 2%2\% per month.

Which Ibis weights give SD[Rp]=2%\text{SD}[R_p] = 2\%?

Which of the two does a mean-variance investor hold?

βœ… Correct! Same 2%2\% risk, but 1.10%>0.83%1.10\% > 0.83\%: the even split dominates, so nobody holds a portfolio on the lower segment of the triangle.
❌ Not quite. At ρ=βˆ’1\rho = -1, SD[Rp]=∣4Ο‰βˆ’8(1βˆ’Ο‰)∣=∣12Ο‰βˆ’8∣\text{SD}[R_p] = |4\omega - 8(1 - \omega)| = |12\omega - 8|. Set that equal to 22.
❌ Close, but… the absolute value gives two cases, 12Ο‰βˆ’8=212\omega - 8 = 2 and 12Ο‰βˆ’8=βˆ’212\omega - 8 = -2, and both weights lie between 00 and 11.
❌ Not quite. Ο‰=23\omega = \tfrac{2}{3} is the zero-risk vertex, where ∣12Ο‰βˆ’8∣=0|12\omega - 8| = 0, and Ο‰=13\omega = \tfrac{1}{3} gives ∣4βˆ’8∣=4%|4 - 8| = 4\%.
❌ Not quite. Compare the two portfolios' expected returns: at equal risk, the higher mean wins.
❌ Not quite. Equal risk is only half the comparison. Their expected returns differ, 1.10%1.10\% against about 0.83%0.83\%, so one dominates the other.
❌ Not quite. Both portfolios have the same 2%2\% risk, so holding more Ibis makes this one no safer, only lower-returning.
Show solution

Step 1: risk at ρ=βˆ’1\rho = -1. The variance is a perfect square, so

SD[Rp]=∣4Ο‰βˆ’8(1βˆ’Ο‰)∣=∣12Ο‰βˆ’8∣\text{SD}[R_p] = |4\omega - 8(1 - \omega)| = |12\omega - 8|

Step 2: solve ∣12Ο‰βˆ’8∣=2|12\omega - 8| = 2. Either 12Ο‰βˆ’8=212\omega - 8 = 2, giving Ο‰=1012=56\omega = \tfrac{10}{12} = \tfrac{5}{6}, or 12Ο‰βˆ’8=βˆ’212\omega - 8 = -2, giving Ο‰=612=12\omega = \tfrac{6}{12} = \tfrac{1}{2}.

Step 3: expected returns.

Ο‰=12:Β 0.5(0.7)+0.5(1.5)=1.10%\omega = \tfrac{1}{2}:\ 0.5(0.7) + 0.5(1.5) = 1.10\% Ο‰=56:Β 56(0.7)+16(1.5)=3.5+1.56β‰ˆ0.83%\omega = \tfrac{5}{6}:\ \tfrac{5}{6}(0.7) + \tfrac{1}{6}(1.5) = \tfrac{3.5 + 1.5}{6} \approx 0.83\%

Step 4: compare. Equal risk, higher expected return: Ο‰Ibis=12\omega_{\text{Ibis}} = \tfrac{1}{2} dominates. The 56\tfrac{5}{6} mix lies on the segment from Ibis to the vertex, and every portfolio there has a twin on the upper segment with the same risk and more return.

Problem 4 Β· Shorting at Perfect Correlation

Given: suppose instead the illustrative Ibis (0.7%0.7\%, 4%4\%) and Jacana (1.5%1.5\%, 8%8\%) had correlation ρ=+1\rho = +1. An investor shorts Jacana and puts the proceeds into Ibis: Ο‰Ibis=1.25\omega_{\text{Ibis}} = 1.25, Ο‰Jacana=βˆ’0.25\omega_{\text{Jacana}} = -0.25.

What is the portfolio's standard deviation?

Does this portfolio dominate holding Ibis alone?

βœ… Correct! Lower risk (3%<4%3\% < 4\%) and lower return (0.50%<0.7%0.50\% < 0.7\%): a trade-off along the straight line, not dominance.
❌ Not quite. Put the signed weights into the full variance formula; the cross term is negative because one weight is negative.
❌ Not quite. 1.25Γ—4+0.25Γ—8=71.25 \times 4 + 0.25 \times 8 = 7 treats the short as a long position. With Ο‰Jacana=βˆ’0.25\omega_{\text{Jacana}} = -0.25 the weighted SDs subtract: ∣5βˆ’2∣=3|5 - 2| = 3.
❌ Not quite. At ρ=+1\rho = +1 long-only mixes cannot get below Ibis's risk, but a short position can: the variance is 25+4βˆ’20=925 + 4 - 20 = 9.
❌ Not quite. 25+4\sqrt{25 + 4} drops the cross term 2(1.25)(βˆ’0.25)(4)(8)(1)=βˆ’202(1.25)(-0.25)(4)(8)(1) = -20, which is large at ρ=+1\rho = +1.
❌ Not quite. Dominance needs both lower risk and at least as much expected return. Work out E[Rp]\text{E}[R_p] with the signed weights.
❌ Not quite. Lower risk alone is not dominance. The short Jacana position also lowers the expected return, to 0.50%0.50\%.
❌ Not quite. The expected return changes with the weights: 1.25(0.7)βˆ’0.25(1.5)=0.50%1.25(0.7) - 0.25(1.5) = 0.50\%, not 0.7%0.7\%.
Show solution

Variance in %2\%^2, with the signed weights:

Var[Rp]=1.252(16)+(βˆ’0.25)2(64)+2(1.25)(βˆ’0.25)(4)(8)(1)=25+4βˆ’20=9\text{Var}[R_p] = 1.25^2(16) + (-0.25)^2(64) + 2(1.25)(-0.25)(4)(8)(1) = 25 + 4 - 20 = 9

So SD[Rp]=9=3%\text{SD}[R_p] = \sqrt{9} = 3\%. At ρ=+1\rho = +1 the variance is the perfect square (1.25Γ—4βˆ’0.25Γ—8)2=(5βˆ’2)2(1.25 \times 4 - 0.25 \times 8)^2 = (5 - 2)^2, which gives the same answer.

Expected return: 1.25(0.7)βˆ’0.25(1.5)=0.875βˆ’0.375=0.50%1.25(0.7) - 0.25(1.5) = 0.875 - 0.375 = 0.50\%.

The portfolio has less risk than Ibis (3%<4%3\% < 4\%) but also less expected return (0.50%<0.7%0.50\% < 0.7\%). At ρ=+1\rho = +1 the only way below Ibis's risk is to short Jacana, and that lowers the return along with the risk, so it is a trade-off, not dominance.

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