Finance-Theory ยท Unit 20 ยท Video 3 ยท Interactive Practice

After-Tax Cash Flow and the Depreciation Tax Shield

IKey Formulas

FormulaNameWhat you need
OP=Revenuesโˆ’Opexw/oย D\text{OP} = \text{Revenues} - \text{Opex}_{\text{w/o } D}Operating profitCash revenues and cash operating expenses
Taxes=ฯ„โ‹…OPโˆ’ฯ„โ‹…D\text{Taxes} = \tau \cdot \text{OP} - \tau \cdot DProject income taxesTax rate ฯ„\tau, depreciation DD
CF=(1โˆ’ฯ„)โ€‰OPโˆ’CapEx+ฯ„D\text{CF} = (1 - \tau)\,\text{OP} - \text{CapEx} + \tau DAfter-tax cash flowAll of the above, plus capital expenditures
D=CostLifeD = \dfrac{\text{Cost}}{\text{Life}}, shield =ฯ„D= \tau DStraight-line depreciation and its tax shieldAsset cost and useful life

Key Insight: Depreciation is not a cash payment; it reaches the cash flow only through the tax it saves, ฯ„D\tau D. In every year of the asset's life, after-tax earnings fall short of after-tax cash flow by exactly DD.

IITwo Routes from the Same Machine

Equipment costing $600,000, depreciated over 6 years: the accountant subtracts DD, the cash flow subtracts only the tax.

IIISame Totals, Different Timing

The same project at ฯ„=25%\tau = 25\% (cost $600,000, revenues $420,000, operating expenses $180,000): cash flow $205,000 and after-tax earnings $105,000 a year. Over the whole life the two streams add up to the same total, but the cash leaves at date 0.

๐Ÿ’ก An NPV discounts each date's cash, so the stream you choose matters: the earnings column spreads the $600,000 outlay over six years that the cash column pays at date 0.

IVThe Schedule Moves the Shield, Not Its Total

A faster depreciation schedule changes when the tax shield arrives, never how much it adds up to.

๐Ÿ’ก Current US law lets most qualifying equipment acquired after 19 January 2025 be written off in full in its first year; the shields still sum to ฯ„ร—Cost\tau \times \text{Cost}, they simply arrive sooner.

VQuiz Questions

Problem 1 ยท Annual After-Tax Cash Flow

Given: equipment costing $600,000, depreciated straight-line over 6 years; revenues $450,000 a year, operating expenses (without depreciation) $190,000 a year, tax rate ฯ„=15%\tau = 15\%. Find the after-tax cash flow in each of years 1โ€“6.

โœ… Correct! The project keeps 85% of its $260,000 operating profit and adds the $15,000 tax shield.
โŒ Not quite. That is (1โˆ’ฯ„)โ€‰OP(1 - \tau)\,\text{OP} alone. Depreciation lowers the tax bill, and the saving ฯ„D\tau D is cash that stays in the firm.
โŒ Not quite. Depreciation is not a cash inflow; only the tax it saves, ฯ„D=0.15ร—100,000\tau D = 0.15 \times 100{,}000, enters the cash flow, not the full DD.
โŒ Not quite. That is the after-tax accounting earnings, (1โˆ’ฯ„)(OPโˆ’D)(1 - \tau)(\text{OP} - D). It subtracts depreciation as if cash left the firm, so it understates the cash by DD.
โŒ Not quite. Use CF=(1โˆ’ฯ„)โ€‰OP+ฯ„D\text{CF} = (1 - \tau)\,\text{OP} + \tau D with no capital expenditure in years 1โ€“6.
Show solution

Straight-line depreciation and operating profit:

D=600,0006=100,000,OP=450,000โˆ’190,000=260,000D = \frac{600{,}000}{6} = 100{,}000, \qquad \text{OP} = 450{,}000 - 190{,}000 = 260{,}000

There is no capital expenditure in years 1โ€“6, so

CF=(1โˆ’0.15)(260,000)+0.15(100,000)=221,000+15,000=236,000\text{CF} = (1 - 0.15)(260{,}000) + 0.15(100{,}000) = 221{,}000 + 15{,}000 = 236{,}000

The after-tax cash flow is $236,000 a year. Check through the tax bill: taxable income is 260,000โˆ’100,000=160,000260{,}000 - 100{,}000 = 160{,}000, the tax is 0.15ร—160,000=24,0000.15 \times 160{,}000 = 24{,}000, and 260,000โˆ’24,000=236,000260{,}000 - 24{,}000 = 236{,}000.

Problem 2 ยท A Faster Schedule

Given: the same project (cost $600,000, revenues $420,000, operating expenses $180,000), now with ฯ„=20%\tau = 20\%. The firm switches from 6-year to 4-year straight-line depreciation. Find the change in the project's year-1 after-tax cash flow.

โœ… Correct! The extra $50,000 of year-1 depreciation saves 0.20ร—50,0000.20 \times 50{,}000 of tax, and that saving is cash.
โŒ Close, butโ€ฆ Depreciation itself is non-cash, yet it is deductible: a larger deduction lowers the tax actually paid, and the tax is a cash outflow.
โŒ Not quite. That is the change in after-tax earnings, โˆ’(1โˆ’ฯ„)โ€‰ฮ”D-(1 - \tau)\,\Delta D. Earnings fall because the accountant subtracts the larger charge; the cash rises because the tax bill shrinks.
โŒ Not quite. The extra $50,000 of depreciation is not cash received; only the tax it saves, ฯ„โ€‰ฮ”D\tau\,\Delta D, changes the cash flow.
โŒ Not quite. Only the shield term ฯ„D\tau D depends on the schedule.
Show solution

Year-1 depreciation rises from 600,000/6=100,000600{,}000/6 = 100{,}000 to 600,000/4=150,000600{,}000/4 = 150{,}000, so ฮ”D=50,000\Delta D = 50{,}000. In CF=(1โˆ’ฯ„)โ€‰OP+ฯ„D\text{CF} = (1 - \tau)\,\text{OP} + \tau D only the last term changes:

ฮ”CF=ฯ„โ€‰ฮ”D=0.20ร—50,000=10,000\Delta \text{CF} = \tau\,\Delta D = 0.20 \times 50{,}000 = 10{,}000

Directly: 0.8(240,000)+0.2(150,000)=222,0000.8(240{,}000) + 0.2(150{,}000) = 222{,}000 versus 0.8(240,000)+0.2(100,000)=212,0000.8(240{,}000) + 0.2(100{,}000) = 212{,}000, an increase of $10,000. After-tax earnings move the other way, from 0.8(140,000)=112,0000.8(140{,}000) = 112{,}000 to 0.8(90,000)=72,0000.8(90{,}000) = 72{,}000, a fall of $40,000.

Problem 3 ยท The Date-by-Date Table

Given: equipment costing $600,000 bought at date 0, depreciated straight-line over 6 years; revenues $400,000 and operating expenses $170,000 in each of years 1โ€“6; ฯ„=35%\tau = 35\%. Find the annual after-tax cash flow, the tax actually paid each year, and the sum of the after-tax cash flows at dates 0โ€“6.

After-tax cash flow in each of years 1โ€“6?

Tax actually paid each year?

Sum of the after-tax cash flows at dates 0โ€“6?

โœ… Correct! The undiscounted cash total equals six years of after-tax earnings, 6ร—84,500=507,0006 \times 84{,}500 = 507{,}000: the streams differ only in timing.
โŒ Check the cash flow. That is (1โˆ’ฯ„)โ€‰OP(1 - \tau)\,\text{OP} alone. Depreciation lowers the tax bill, and the saving ฯ„D=35,000\tau D = 35{,}000 is cash that stays in the firm.
โŒ Check the cash flow. That is the after-tax accounting earnings, (1โˆ’ฯ„)(OPโˆ’D)(1 - \tau)(\text{OP} - D). It subtracts depreciation as if cash left the firm each year, so it understates the cash by DD.
โŒ Check the cash flow. That adds the whole DD back to (1โˆ’ฯ„)โ€‰OP(1 - \tau)\,\text{OP}. Depreciation is not a cash inflow; only the tax it saves, ฯ„D\tau D, enters the cash flow.
โŒ Check the tax. That is ฯ„ร—OP\tau \times \text{OP}, the tax with no depreciation deduction. Taxable income is operating profit minus depreciation.
โŒ Check the tax. That is the tax shield ฯ„D\tau D, the tax the deduction saves, not the tax paid.
โŒ Check the tax. That is the taxable income, OPโˆ’D\text{OP} - D. The tax is ฯ„\tau times it.
โŒ Check the sum. That adds the six annual cash flows but leaves out date 0, where the $600,000 purchase is a negative cash flow.
โŒ Check the sum. Nothing forces the undiscounted total to zero: it is the date-0 outlay plus six positive annual cash flows.
โŒ Check the sum. That charges the $600,000 twice: once at date 0 and again through the depreciation inside six years of after-tax earnings. Dates 1โ€“6 carry the cash flow, not the earnings.
โŒ Check the cash flow. Keep 1โˆ’ฯ„1 - \tau of operating profit and add the shield ฯ„D\tau D, not the whole DD and not nothing.
โŒ Check the tax. The tax is ฯ„\tau times taxable income, and taxable income is operating profit minus depreciation.
โŒ Check the sum. Date 0 carries the $600,000 purchase as a negative cash flow; dates 1โ€“6 each carry the annual after-tax cash flow.
Show solution

D=600,000/6=100,000D = 600{,}000/6 = 100{,}000 and OP=400,000โˆ’170,000=230,000\text{OP} = 400{,}000 - 170{,}000 = 230{,}000. In each year t=1,โ€ฆ,6t = 1, \dots, 6:

CFt=(1โˆ’0.35)(230,000)+0.35(100,000)=149,500+35,000=184,500\text{CF}_t = (1 - 0.35)(230{,}000) + 0.35(100{,}000) = 149{,}500 + 35{,}000 = 184{,}500 Taxes=0.35ร—230,000โˆ’0.35ร—100,000=80,500โˆ’35,000=45,500\text{Taxes} = 0.35 \times 230{,}000 - 0.35 \times 100{,}000 = 80{,}500 - 35{,}000 = 45{,}500

Check: 230,000โˆ’45,500=184,500230{,}000 - 45{,}500 = 184{,}500. The date-0 cash flow is the capital expenditure, โˆ’600,000-600{,}000, so

โˆ‘t=06CFt=โˆ’600,000+6ร—184,500=507,000\sum_{t=0}^{6} \text{CF}_t = -600{,}000 + 6 \times 184{,}500 = 507{,}000

Annual cash flow $184,500, tax $45,500, total $507,000. After-tax earnings are 0.65ร—130,000=84,5000.65 \times 130{,}000 = 84{,}500 a year and also sum to 507,000507{,}000, because the six depreciation charges add up to the $600,000 outlay.

Problem 4 ยท Full Write-Off in Year 1

Given: the same equipment (cost $600,000), now with revenues $380,000 and operating expenses $160,000 in each of years 1โ€“6, ฯ„=30%\tau = 30\%, but the full $600,000 is deducted as depreciation in year 1 and nothing afterwards. The project shows a taxable loss in year 1; the firm's other profits absorb it, so the whole tax shield is realised that year. Find the after-tax cash flow in year 1 and in year 2.

Year-1 after-tax cash flow?

Year-2 after-tax cash flow?

โœ… Correct! The whole $180,000 of shield arrives in year 1 instead of $30,000 a year; the cash total over years 1โ€“6 is unchanged at $1,104,000.
โŒ Check year 1. That is the 6-year straight-line cash flow, with a $100,000 deduction. Here the whole $600,000 is deducted in year 1, so the shield is ฯ„ร—600,000\tau \times 600{,}000.
โŒ Check year 1. That is (1โˆ’ฯ„)โ€‰OP(1 - \tau)\,\text{OP} with no shield. The $600,000 deduction saves 0.30ร—600,0000.30 \times 600{,}000 of tax in year 1, and that saving is cash.
โŒ Check year 1. That is the after-tax accounting result, (1โˆ’ฯ„)(OPโˆ’D1)(1 - \tau)(\text{OP} - D_1), which charges the whole $600,000 as if it were paid in year 1. The cash flow adds the depreciation back: only the tax saved enters.
โŒ Check year 2. That still counts a $30,000 shield from 6-year straight-line. After a full write-off, D2=0D_2 = 0 and there is no shield left.
โŒ Check year 2. The asset is fully depreciated, but the project still earns operating profit; it keeps 1โˆ’ฯ„1 - \tau of it.
โŒ Check year 2. That is the operating profit before tax. With D2=0D_2 = 0 the full operating profit is taxed, so the project keeps (1โˆ’ฯ„)โ€‰OP(1 - \tau)\,\text{OP}.
โŒ Check year 1. CF1=(1โˆ’ฯ„)โ€‰OP+ฯ„D1\text{CF}_1 = (1 - \tau)\,\text{OP} + \tau D_1 with D1=600,000D_1 = 600{,}000. The accounting loss, (1โˆ’ฯ„)(OPโˆ’D1)(1 - \tau)(\text{OP} - D_1), is not the cash flow.
โŒ Check year 2. With nothing left to depreciate, D2=0D_2 = 0: the project keeps 1โˆ’ฯ„1 - \tau of its operating profit and has no shield.
Show solution

OP=380,000โˆ’160,000=220,000\text{OP} = 380{,}000 - 160{,}000 = 220{,}000 every year. Depreciation is D1=600,000D_1 = 600{,}000 and D2=โ‹ฏ=D6=0D_2 = \dots = D_6 = 0.

CF1=(1โˆ’0.30)(220,000)+0.30(600,000)=154,000+180,000=334,000\text{CF}_1 = (1 - 0.30)(220{,}000) + 0.30(600{,}000) = 154{,}000 + 180{,}000 = 334{,}000 CF2=(1โˆ’0.30)(220,000)+0.30(0)=154,000\text{CF}_2 = (1 - 0.30)(220{,}000) + 0.30(0) = 154{,}000

Year 1 is $334,000 and years 2โ€“6 are $154,000 each. The project's year-1 tax is 0.30(220,000โˆ’600,000)=โˆ’114,0000.30(220{,}000 - 600{,}000) = -114{,}000: the firm's other profits absorb the loss, so the project lowers the firm's total tax bill by $114,000. Under 6-year straight-line the cash flow would be 0.7(220,000)+0.3(100,000)=184,0000.7(220{,}000) + 0.3(100{,}000) = 184{,}000 every year. Both schedules give 334,000+5ร—154,000=6ร—184,000=1,104,000334{,}000 + 5 \times 154{,}000 = 6 \times 184{,}000 = 1{,}104{,}000 over years 1โ€“6; the write-off simply moves $150,000 of shield into year 1, which raises the NPV at any positive discount rate.

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