Finance-Theory Β· Unit 9 Β· Video 3 Β· Interactive Practice

A Share Is Worth Its Dividends: Deriving the Dividend Discount Model

IKey Formulas

FormulaNameWhat it says
Pt=Et[Dt+1+Pt+1]1+rP_t = \dfrac{\mathsf{E}_t[D_{t+1} + P_{t+1}]}{1+r}One-year pricingToday's price is the expected dividend plus the expected ex-dividend resale price one year out, discounted one year at a rate held fixed at rr
Pt=βˆ‘k=1NEt[Dt+k](1+r)k+Et[Pt+N](1+r)NP_t = \displaystyle\sum_{k=1}^{N} \frac{\mathsf{E}_t[D_{t+k}]}{(1+r)^k} + \frac{\mathsf{E}_t[P_{t+N}]}{(1+r)^N}After NN substitutionsSubstituting each year's price forward uses Et[Et+1[X]]=Et[X]\mathsf{E}_t\big[\mathsf{E}_{t+1}[X]\big] = \mathsf{E}_t[X] and (1+r)(1+r)=(1+r)2(1+r)(1+r) = (1+r)^2; the last piece is the resale term
lim⁑Nβ†’βˆžEt[Pt+N](1+r)N=0\displaystyle\lim_{N\to\infty} \frac{\mathsf{E}_t[P_{t+N}]}{(1+r)^N} = 0No-bubble conditionAn assumption: the expected price does not keep growing as fast as rr forever
Ptβ‰‘βˆ‘k=1∞Et[Dt+k](1+rt+k)kP_t \equiv \displaystyle\sum_{k=1}^{\infty} \frac{\mathsf{E}_t[D_{t+k}]}{(1+r_{t+k})^k}Dividend discount modelOne risk-adjusted rate per horizon, like a spot rate; dividends satisfy Dtβ‰₯0D_t \ge 0 and prices are ex-dividend

Key Insight: A claim that never pays anything is worth nothing. With every dividend zero, the price equals the discounted expected resale price for every NN, so the expected price would have to grow at exactly rr forever; the no-bubble condition rules that out and leaves Pt=0P_t = 0.

IISubstituting Forward Moves Value, Not Price

Each substitution turns part of the resale term into a discounted dividend and leaves the price unchanged.

IIIA Claim That Never Pays

With every dividend zero, today's price can rest only on an expected resale price growing at exactly rr.

IVOne Rate per Horizon

Each expected dividend is discounted at the risk-adjusted rate for its own horizon, raised to that horizon.

VQuiz Questions

Problem 1 Β· Price One Year at a Time

Given: A share is expected to pay a dividend of $2 one year from now and then to sell, ex-dividend, for an expected $53. The risk-adjusted rate is r=10%r = 10\%. Find today's price PtP_t.

βœ… Correct! The dividend and the resale price both arrive in one year, so both are discounted: (2+53)/1.1=50(2 + 53)/1.1 = 50.
❌ Not discounted. $55 is what you expect to hold one year from now. Today's price divides it by 1+r1 + r: 55/1.1=5055/1.1 = 50.
❌ The dividend is a year away too. Adding $2 undiscounted to 53/1.1β‰ˆ48.1853/1.1 \approx 48.18 gives about $50.18. The dividend is paid at t+1t+1, so it sits inside the numerator: (2+53)/1.1=50(2 + 53)/1.1 = 50.
❌ Nothing to subtract. Pt+1P_{t+1} is already ex-dividend, so it excludes the $2. Holding the share for the year earns the dividend plus the resale price: (2+53)/1.1=50(2 + 53)/1.1 = 50, not (53βˆ’2)/1.1β‰ˆ46.36(53 - 2)/1.1 \approx 46.36.
❌ Not quite. Use Pt=Et[Dt+1+Pt+1]/(1+r)P_t = \mathsf{E}_t[D_{t+1} + P_{t+1}]/(1+r).
Show solution

Buying today at PtP_t earns, one year from now, the dividend Dt+1D_{t+1} and the ex-dividend price Pt+1P_{t+1}. With the rate held fixed at rr:

Pt=Et[Dt+1+Pt+1]1+r=2+531.10=551.10=50P_t = \frac{\mathsf{E}_t[D_{t+1} + P_{t+1}]}{1+r} = \frac{2 + 53}{1.10} = \frac{55}{1.10} = 50

Today's price is $50.00.

Problem 2 Β· Two Years of Substitution

Given: A share's expected dividends are $1.10 in one year and $1.21 in two years, and its expected ex-dividend price two years from now is $60.50. The risk-adjusted rate is fixed at r=10%r = 10\%. Find today's price using Pt=Et[Dt+1]1+r+Et[Dt+2](1+r)2+Et[Pt+2](1+r)2P_t = \dfrac{\mathsf{E}_t[D_{t+1}]}{1+r} + \dfrac{\mathsf{E}_t[D_{t+2}]}{(1+r)^2} + \dfrac{\mathsf{E}_t[P_{t+2}]}{(1+r)^2}.

βœ… Correct! 1.10/1.1+1.21/1.21+60.50/1.21=1+1+50=521.10/1.1 + 1.21/1.21 + 60.50/1.21 = 1 + 1 + 50 = 52.
❌ Two-year cash flows get two years of discounting. Dividing everything by 1.11.1 gives 62.81/1.1=57.1062.81/1.1 = 57.10. Substituting next year's price in multiplies the two factors: the second dividend and the resale price are divided by (1.1)2=1.21(1.1)^2 = 1.21.
❌ The resale term is still there. The two dividends are worth 1+1=21 + 1 = 2, but after only two substitutions the resale term 60.50/1.21=5060.50/1.21 = 50 remains. It vanishes only as Nβ†’βˆžN \to \infty, and only under the no-bubble condition.
❌ Check the second dividend. It is paid in two years, so it is divided by (1.1)2(1.1)^2: 1.21/1.21=11.21/1.21 = 1, not 1.21/1.1=1.101.21/1.1 = 1.10.
❌ Not quite. Discount each amount by (1.1)k(1.1)^k, where kk is the year in which it arrives.
Show solution

After substituting Pt+1P_{t+1} into today's equation, every amount that arrives in year 2 is divided by (1+r)2=1.21(1+r)^2 = 1.21:

Pt=1.101.1+1.211.21+60.501.21=1+1+50=52P_t = \frac{1.10}{1.1} + \frac{1.21}{1.21} + \frac{60.50}{1.21} = 1 + 1 + 50 = 52

Today's price is $52.00. The same price comes from pricing one year at a time: Pt+1=(1.21+60.50)/1.1=56.10P_{t+1} = (1.21 + 60.50)/1.1 = 56.10, then Pt=(1.10+56.10)/1.1=52P_t = (1.10 + 56.10)/1.1 = 52.

Problem 3 Β· Paying for a Claim That Never Pays

Given: A share will never pay a dividend of any kind, not even a liquidating one. It trades today at $20, and the risk-adjusted rate is held fixed at r=8%r = 8\%. Find the expected price ten years from now that today's $20 requires, and the share's value once the no-bubble condition is imposed.

Expected price in ten years that justifies $20 today?

Value under the no-bubble condition?

βœ… Correct! With no dividends, 20=Et[Pt+10]/(1.08)1020 = \mathsf{E}_t[P_{t+10}]/(1.08)^{10} forces Et[Pt+10]=20Γ—1.0810β‰ˆ43.18\mathsf{E}_t[P_{t+10}] = 20 \times 1.08^{10} \approx 43.18. The resale term equals 20 at every horizon, so it never goes to zero; the no-bubble condition then leaves a value of $0.
❌ Check the required price. With every dividend zero, Pt=Et[Pt+N]/(1+r)NP_t = \mathsf{E}_t[P_{t+N}]/(1+r)^N for every NN; solve for Et[Pt+10]\mathsf{E}_t[P_{t+10}].
❌ That is simple interest. 20Γ—(1+10Γ—0.08)=3620 \times (1 + 10 \times 0.08) = 36. Substituting forward compounds the rate: 20Γ—1.0810β‰ˆ43.1820 \times 1.08^{10} \approx 43.18.
❌ A flat price loses money. A share that pays nothing and is expected to stay at $20 earns 0%, not 8%. Its whole return must come from resale, so the expected price grows at exactly rr: 20Γ—1.0810β‰ˆ43.1820 \times 1.08^{10} \approx 43.18.
❌ Wrong direction. 20/1.0810β‰ˆ9.2620/1.08^{10} \approx 9.26 discounts today's price. The future price must be larger: Et[Pt+10]=20Γ—1.0810β‰ˆ43.18\mathsf{E}_t[P_{t+10}] = 20 \times 1.08^{10} \approx 43.18.
❌ Check the value. With every dividend zero, the sum of discounted expected dividends is zero, and that sum is all the no-bubble condition leaves.
❌ That is the resale term, not a value. At $20 the resale term is Et[Pt+N]/(1.08)N=20\mathsf{E}_t[P_{t+N}]/(1.08)^N = 20 for every NN, so its limit is 20, not 0. That is exactly what the no-bubble condition rules out.
❌ Discounting the price again. 20/1.0810β‰ˆ9.2620/1.08^{10} \approx 9.26 is not a value for anything the share pays. The share pays nothing, so the sum of its discounted expected dividends is $0.
❌ The condition pins it down. Once the resale term must vanish, PtP_t equals the sum of discounted expected dividends, and every one of those is zero, so Pt=0P_t = 0 whatever anyone forecasts for prices.
Show solution

With Dt+k=0D_{t+k} = 0 for all kk, the NN-year formula keeps only the resale term:

Pt=Et[Pt+N](1+r)NforΒ everyΒ NP_t = \frac{\mathsf{E}_t[P_{t+N}]}{(1+r)^N} \quad\text{for every } N

At N=10N = 10:

Et[Pt+10]=20Γ—1.0810β‰ˆ20Γ—2.1589β‰ˆ43.18\mathsf{E}_t[P_{t+10}] = 20 \times 1.08^{10} \approx 20 \times 2.1589 \approx 43.18

The expected price must grow at exactly 8% a year forever, and the resale term equals 20 at every horizon. Each buyer pays only because a later buyer is expected to pay more, for a share that will never pay any of them: the bigger-fool chain. The no-bubble condition requires

lim⁑Nβ†’βˆžEt[Pt+N](1+r)N=0,\lim_{N\to\infty} \frac{\mathsf{E}_t[P_{t+N}]}{(1+r)^N} = 0,

and the only price for which the resale term goes to zero is Pt=0P_t = 0. The share is worth $0; a buyer at $20 hands the seller a free lunch.

Problem 4 Β· Two Horizons, Two Rates

Given: A company is expected to pay a dividend of $5.40 in one year and then, in two years, to liquidate and pay out an expected $60.50 per share as a liquidating dividend; nothing is paid after that. The risk-adjusted rates are rt+1=8%r_{t+1} = 8\% for the one-year horizon and rt+2=10%r_{t+2} = 10\% for the two-year horizon. Find PtP_t from the dividend discount model.

βœ… Correct! 5.40/1.08+60.50/1.102=5+50=555.40/1.08 + 60.50/1.10^2 = 5 + 50 = 55. Each dividend is discounted at its own horizon's rate, raised to its own horizon.
❌ One rate for both horizons. Discounting the year-2 payment at 8% gives 60.50/1.082β‰ˆ51.8760.50/1.08^2 \approx 51.87 and a total of about $56.87. The model gives each horizon its own rate: 60.50/1.102=5060.50/1.10^2 = 50.
❌ Missing the power. The year-2 denominator is (1+rt+2)2(1 + r_{t+2})^2, not 1+rt+21 + r_{t+2}: 60.50/1.21=5060.50/1.21 = 50, not 60.50/1.10=5560.50/1.10 = 55.
❌ The rate is already a two-year rate. rt+2r_{t+2} is the rate for the two-year horizon, like a spot rate, so it is squared: (1.10)2=1.21(1.10)^2 = 1.21. Multiplying (1.08)(1.10)=1.188(1.08)(1.10) = 1.188 treats 10% as a rate for the second year alone and gives about $55.93.
❌ Not quite. Use Pt=βˆ‘kEt[Dt+k]/(1+rt+k)kP_t = \sum_k \mathsf{E}_t[D_{t+k}]/(1 + r_{t+k})^k with one term per payment.
Show solution

The liquidating dividend is a payment like any other, and every later dividend is zero, so the sum has two nonzero terms:

Pt=Et[Dt+1]1+rt+1+Et[Dt+2](1+rt+2)2=5.401.08+60.50(1.10)2=5+60.501.21=5+50=55P_t = \frac{\mathsf{E}_t[D_{t+1}]}{1 + r_{t+1}} + \frac{\mathsf{E}_t[D_{t+2}]}{(1 + r_{t+2})^2} = \frac{5.40}{1.08} + \frac{60.50}{(1.10)^2} = 5 + \frac{60.50}{1.21} = 5 + 50 = 55

Today's price is $55.00.

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