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Pre-Calculus I
Functions
01Relations and Functions: One Input, One Output02Function Notation: Reading f(x) and Functions in Tables03Evaluating and Solving Functions Given by Formulas04Evaluating and Solving from Tables and Graphs05Vertical and Horizontal Line Tests and the Toolkit FunctionsProblem setProblem set 2

Evaluating and Solving Functions Given by Formulas

Why does evaluating a function always give one answer while solving f(x) = k can give several, and how do you simplify a difference quotient?


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Questions

Work each one out before you check it. Every question has a scratch pad and a calculator.

  1. Question 1

    Let f(x)=4−2x2+xf(x) = 4 - 2x^2 + xf(x)=4−2x2+x. Find f(−3)f(-3)f(−3).

    f(−3)=f(-3) =f(−3)=
  2. Question 2

    Let f(x)=2x2−5xf(x) = 2x^2 - 5xf(x)=2x2−5x. Find f(a+3)f(a + 3)f(a+3) and simplify it to the form 2a2+Ba+C2a^2 + Ba + C2a2+Ba+C.

    B=B =B=
    C=C =C=
  3. Question 3

    Let g(x)=x2−6xg(x) = x^2 - 6xg(x)=x2−6x. For h≠0h \neq 0h=0, simplify g(a+h)−g(a)h\dfrac{g(a+h) - g(a)}{h}hg(a+h)−g(a)​ to the form pa+qh+rpa + qh + rpa+qh+r.

    p=p =p=
    q=q =q=
    r=r =r=
  4. Question 4

    Let h(p)=p2−2ph(p) = p^2 - 2ph(p)=p2−2p. Solve h(p)=8h(p) = 8h(p)=8.

    smaller solution: p=p =p=
    larger solution: p=p =p=
  5. Question 5

    Express the relationship 5x−2y=85x - 2y = 85x−2y=8 as a function y=f(x)y = f(x)y=f(x), in the form f(x)=mx+cf(x) = mx + cf(x)=mx+c.

    m=m =m=
    c=c =c=
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