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01Series Approximations: Keeping One or Two Terms02Integrals as Sums: Along a Line and a Curved Path03Line Integrals: Work as the Integral of F · ds04Closed Line Integrals: Work Around a Loop05Double Integrals: Area, Charge and Volume06Closed Surface Integrals: The Sphere and Its Charge07Electric Flux Through Surfaces and Volume IntegralsProblem set0/10Problem set 20/10MIT problem set0/4
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Electrostatics
01Coulomb's Law: Force Between Two Point Charges02Superposition: Adding Coulomb Forces as Vectors03Field Lines, Null Points and Uniform Fields04The Electric Dipole and Its 1/r³ Field05Torque, Energy and Force on a Dipole in a FieldProblem set0/10Problem set 20/10MIT problem set0/1

Coulomb's Law: Force Between Two Point Charges

Why does the force between two point charges fall off as 1/r², and how does Coulomb's law fix its direction?


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Your summary note

    1. 1

      Two kinds of charge, quantization and conservation

      Record Franklin's sign convention, that like charges repel and opposite charges attract, the value e=1.602×10−19e = 1.602 \times 10^{-19}e=1.602×10−19 C, and the statements that charge comes in multiples of eee and is conserved.

    2. 2

      Coulomb's law F⃗12=keq1q2r2r^\vec{F}_{12} = k_e \frac{q_1 q_2}{r^2}\hat{r}F12​=ke​r2q1​q2​​r^

      Write the vector law with r^\hat{r}r^ pointing from q1q_1q1​ to q2q_2q2​, state F⃗21=−F⃗12\vec{F}_{21} = -\vec{F}_{12}F21​=−F12​, and sketch the like-sign and opposite-sign cases showing how the sign of q1q2q_1 q_2q1​q2​ sets the direction.

    3. 3

      The Coulomb constant and the permittivity of free space

      Write ke=1/(4πε0)=8.9875×109 N⋅m2/C2k_e = 1/(4\pi\varepsilon_0) = 8.9875 \times 10^9\ \text{N} \cdot \text{m}^2/\text{C}^2ke​=1/(4πε0​)=8.9875×109 N⋅m2/C2, compute ε0=1/(μ0c2)\varepsilon_0 = 1/(\mu_0 c^2)ε0​=1/(μ0​c2) from μ0=4π×10−7\mu_0 = 4\pi \times 10^{-7}μ0​=4π×10−7 and ccc, and carry the units to C2/(N⋅m2)\text{C}^2/(\text{N} \cdot \text{m}^2)C2/(N⋅m2).

    Attempt 1 of 2