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Electricity and Magnetism
Mathematical Tools and Fields
01Series Approximations: Keeping One or Two Terms02Integrals as Sums: Along a Line and a Curved Path03Line Integrals: Work as the Integral of F · ds04Closed Line Integrals: Work Around a Loop05Double Integrals: Area, Charge and Volume06Closed Surface Integrals: The Sphere and Its Charge07Electric Flux Through Surfaces and Volume IntegralsProblem set0/10Problem set 20/10MIT problem set0/4
01Field Theory Versus Action at a Distance02Scalar Fields: Contour, Color and Relief Maps03Vector Fields, Sources, Sinks and Divergence04Curl: Measuring the Circulation of a Field05Gravitational, Electric and Magnetic Fields06Drawing Vector Fields: Arrows, Lines and Grass SeedsProblem set0/10Problem set 20/10MIT problem set0/1
Electrostatics
01Coulomb's Law: Force Between Two Point Charges02Superposition: Adding Coulomb Forces as Vectors03Field Lines, Null Points and Uniform Fields04The Electric Dipole and Its 1/r³ Field05Torque, Energy and Force on a Dipole in a FieldProblem set0/10Problem set 20/10MIT problem set0/1

The Electric Dipole and Its 1/r³ Field

Why does a dipole's field fall off as 1/r³ instead of 1/r², and which way does it point far away?


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Your summary note

    1. 1

      Dipole moment p⃗=2qa j^\vec{p} = 2qa\,\hat{j}p​=2qaj^​

      Define p⃗\vec{p}p​ for ±q\pm q±q separated by 2a2a2a, pointing from −q-q−q to +q+q+q, give p⃗=∑iqir⃗i\vec{p} = \sum_i q_i \vec{r}_ip​=∑i​qi​ri​ for a neutral system, and name polar molecules and induced dipoles as examples.

    2. 2

      Exact field components from two point charges

      Superpose the fields of +q+q+q at y=ay = ay=a and −q-q−q at y=−ay = -ay=−a to write ExE_xEx​ and EyE_yEy​ at P(x,y,0)P(x, y, 0)P(x,y,0) in terms of xxx, yyy and aaa.

    3. 3

      The point-dipole limit r≫ar \gg ar≫a

      Reduce the exact components to Ex=3psin⁡θcos⁡θ4πε0r3E_x = \frac{3p\sin\theta\cos\theta}{4\pi\varepsilon_0 r^3}Ex​=4πε0​r33psinθcosθ​ and Ey=p(3cos⁡2θ−1)4πε0r3E_y = \frac{p(3\cos^2\theta - 1)}{4\pi\varepsilon_0 r^3}Ey​=4πε0​r3p(3cos2θ−1)​, then assemble the vector form using p⃗⋅r⃗\vec{p} \cdot \vec{r}p​⋅r.

    4. 4

      Inverse-cube falloff and the two field-line pictures

      Contrast the dipole's 1/r31/r^31/r3 falloff with a point charge's 1/r21/r^21/r2, tie it to the dipole's zero net charge, and sketch the finite-dipole and point-dipole field lines side by side.

    Attempt 1 of 2