How do the axioms alone force 0v = 0, and why do just three checks prove that a subset is a subspace?
Loading…
Unique additive identity and unique additive inverse
Prove that has only one additive identity and each only one additive inverse as chains of equalities with each step's axiom labelled, then define and .
and
Derive each from using the matching distributive property, cancel with an additive inverse, and record which is a scalar and which is a vector in each statement.
Write the chain naming the axiom or result behind each step, and conclude with uniqueness of additive inverses.
The conditions for a subspace
State the definition of a subspace and the three conditions, prove both directions including how comes from , and note that nonempty can replace .