Why can a positive operator have infinitely many square roots but only one positive one, and how do you compute √T?
Loading…
Proof that a positive square root is determined
For an eigenvector of with eigenvalue , expand in an orthonormal eigenbasis of , compare with , and conclude , which fixes .
Many square roots, only one positive
Record the definition of , and show that the identity operator has infinitely many square roots when while only itself is positive.
Computing and on
For and , verify positivity, take square roots of the eigenvalues in an orthonormal eigenbasis, and write the matrices of and in the standard basis.
Positive with forces
Rewrite as using self-adjointness of , and deduce and then .