Ludium
Sign In
Single Variable Calculus
Differentiation
01The Derivative as the Slope of the Tangent Line02Secant Lines and the Limit Definition of the Derivative03Differentiating 1/x Straight From the Definition04Tangents to 1/x and the Triangle of Area 205Newton and Leibniz Notation, and the Power RuleProblem set0/10Problem set 20/10MIT problem set0/3Practice∞
01The Derivative as an Instantaneous Rate of Change02Rates of Change Without Time: Gradient and Sensitivity03Easy Limits, 0/0, and One-Sided Limits04Continuity, Jumps, and Removable Discontinuities05Infinite Discontinuities: 1/x and Its Derivative06Differentiable Implies ContinuousProblem set0/10Problem set 20/10Practice∞
01Two Kinds of Formula, and the Derivative of Sine02The Derivative of Cosine, and Two Limits at Zero03Bow and Bowstring: Proving the Two Trig Limits04Why the Trig Derivatives Hold Only in Radians05A Geometric Proof: Sine as a Height on the Circle06Finishing the Proof, and the Product and Quotient RulesProblem set0/10Problem set 20/10MIT problem set0/1Practice∞
01Proving the Product Rule: Change One Factor at a Time02The Quotient Rule, and the Power Rule for Negative Exponents03The Chain Rule: Differentiating a Function of a Function04Higher Derivatives: The Sine Cycle and Three Notations05The nth Derivative of xⁿ Is n Factorial, by InductionProblem set0/10Problem set 20/10MIT problem set0/2Practice∞
01The Power Rule for Rational Exponents02The Slope of a Circle, Two Ways03Implicit Differentiation of a Quartic Curve04Inverse Functions and the Reflection Across y = x05Derivatives of the Arctangent and ArcsineProblem set0/10Problem set 20/10MIT problem set0/1Practice∞

Two Kinds of Formula, and the Derivative of Sine

Why does the sine difference quotient collapse only when its terms are regrouped so a vanishing numerator sits over a vanishing denominator?


Loading…

←Previous Differentiable Implies ContinuousNext The Derivative of Cosine, and Two Limits at Zero →

Your summary note

    1. 1

      Specific formulas versus general formulas

      Record the distinction, listing ddxxn=nxn−1\frac{d}{dx}x^n=nx^{n-1}dxd​xn=nxn−1 and ddx(1/x)=−1/x2\frac{d}{dx}(1/x)=-1/x^2dxd​(1/x)=−1/x2 against (u+v)′=u′+v′(u+v)'=u'+v'(u+v)′=u′+v′ and (cu)′=cu′(cu)'=cu'(cu)′=cu′, and note that a polynomial needs both kinds at once.

    2. 2

      The sine sum formula in the difference quotient

      Write sin⁡(x+Δx)−sin⁡xΔx\frac{\sin(x+\Delta x)-\sin x}{\Delta x}Δxsin(x+Δx)−sinx​ and expand the first term by sin⁡(a+b)=sin⁡acos⁡b+cos⁡asin⁡b\sin(a+b)=\sin a\cos b+\cos a\sin bsin(a+b)=sinacosb+cosasinb with a=xa=xa=x and b=Δxb=\Delta xb=Δx, carrying along the trailing −sin⁡x-\sin x−sinx.

    3. 3

      The regrouping that keeps a zero over a zero

      Pair sin⁡xcos⁡Δx\sin x\cos\Delta xsinxcosΔx with −sin⁡x-\sin x−sinx, factor out sin⁡x\sin xsinx, write the two brackets cos⁡Δx−1Δx\frac{\cos\Delta x-1}{\Delta x}ΔxcosΔx−1​ and sin⁡ΔxΔx\frac{\sin\Delta x}{\Delta x}ΔxsinΔx​, and note that a 1/01/01/0 term would be fatal.

    4. 4

      The granted limits AAA and BBB, and ddxsin⁡x=cos⁡x\frac{d}{dx}\sin x=\cos xdxd​sinx=cosx

      State (A) (cos⁡Δx−1)/Δx→0(A)\ (\cos\Delta x-1)/\Delta x\to0(A) (cosΔx−1)/Δx→0 and (B) sin⁡Δx/Δx→1(B)\ \sin\Delta x/\Delta x\to1(B) sinΔx/Δx→1, then finish the limit, killing the first term and keeping the factor cos⁡x\cos xcosx.

    Attempt 1 of 2