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Differential Equations
The Geometric View of ODEs
01Direction Fields and the Geometric View of ODEs02Integral Curves and the Isocline Method03Perpendicular Isoclines: The Circles of y' = -x/y04Isocline Corridors and a Trap for Solutions05Existence and Uniqueness: One Curve Through a Point06Where Existence and Uniqueness FailProblem set0/10Problem set 20/10MIT problem set0/3
Numerical Methods
01Euler's Method and Its Three Equations02Euler's Method by Hand: Building the Table03Convexity and the Sign of Euler's Error04First Order Error: Halve the Step, Halve the Error05Improved Euler (RK2): Averaging Two Slopes06Runge-Kutta 4 and the Price of Accuracy07Singular Points: Where Every Method FailsProblem set0/10Problem set 20/10MIT problem set0/1
First-Order Linear Equations
01First Order Linear: Standard Form and the Sign of p02The Conduction-Diffusion Model: Newton's Law of Cooling03The Integrating Factor and the Four-Step Method04Integrating Factors: Two Mistakes and a Trick Question05Constant Coefficients: Steady State and TransientProblem set0/10Problem set 20/10MIT problem set0/1
Substitution Methods
01Scaling a First Order ODE: The Fourth-Power Cooling Law02The Bernoulli Equation and the Substitution v = y^(1-n)03A Worked Bernoulli Example: The Substitution v = 1/y04Homogeneous Equations: The Zoom Test and y = zx05Modelling the Lighthouse Chase: A 45-Degree Heading06The Boat's Path: A Logarithmic Spiral in Polar CoordinatesProblem set0/10Problem set 20/10
Autonomous Equations
01Autonomous Equations and Time-Translation Invariance02Critical Points: Constant Solutions as Barriers03The Embezzler Model dy/dt = ry - w: One Unstable Balance04The Logistic Equation: Carrying Capacity Without Solving05Stable, Unstable and Semi-Stable Critical Points06Maximum Sustainable Harvest: Why h = a^2/4bProblem set0/10Problem set 20/10MIT problem set0/3
Complex Numbers
01Complex Division, Polar Form and the Definition of e^(iθ)02Why e^(iθ) Earns Its Name: Multiply Moduli, Add Angles03Integrating e^(-x) cos x by Complexifying04The nth Roots of Unity: Zeta on the Unit CircleProblem set0/10Problem set 20/10MIT problem set0/4
Input and Response
01Steady-State and Transient Solutions of y' + ky = q(t)02Input, Response and the Superposition Principle03Solving y' + ky = k cos ωt by Complexification04Amplitude and Phase Lag of a Sinusoidal ResponseProblem set0/10Problem set 20/10MIT problem set0/2
01Cartesian Method: Rationalise, Then Take the Real Part02The Sinusoidal Identity and Its Right Triangle03Three Proofs of the Sinusoidal Identity04The Mixing Tank: Salt Balance and k = r/V05RC Circuits, Decay Chains and Negative kProblem set0/10Problem set 20/10MIT problem set0/2
Second-Order Linear Equations
01Second-Order Linear ODEs and the Spring–Mass–Dashpot02The Characteristic Equation and Overdamped Motion03Complex Roots a ± bi and Underdamped Oscillation04Critical Damping and Reduction of Order: t e^(−at)Problem set0/10Problem set 20/10MIT problem set0/2
01One Complex Root Is Enough: Conjugates and Real Solutions02When a Damped Spring Oscillates: p Below ω₀03Damped Oscillations: Pseudo-Period and ω₁² + p² = ω₀²Problem set0/10Problem set 20/10MIT problem set0/1
01Superposition: Why Linearity Makes c₁y₁ + c₂y₂ a Solution02The Wronskian and Abel's Theorem: Fitting Any Initial Values03Normalized Solutions: Why cosh x and sinh x Solve y'' − y = 004Uniqueness: Why c₁y₁ + c₂y₂ Is Every SolutionProblem set0/10Problem set 20/10

Constant Coefficients: Steady State and Transient

Why does the initial temperature $T_0$ stop mattering once $e^{-kt}$ decays, leaving only the steady-state integral?


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Your summary note

    1. 1

      Standard form dTdt+kT=kTe\frac{dT}{dt} + kT = kT_edtdT​+kT=kTe​

      Write the conduction equation in standard form with kTekT_ekTe​ on the right rather than TeT_eTe​, and carry out the units comparison of the two sides.

    2. 2

      The integrating factor ekte^{kt}ekt

      Integrate k dtk\,dtkdt, multiply through, write the compact form (ektT)′=kTe(t)ekt(e^{kt}T)' = kT_e(t)e^{kt}(ektT)′=kTe​(t)ekt, and integrate to T=e−kt∫kTe(t)ekt dt+Ce−ktT = e^{-kt}\int kT_e(t)e^{kt}\,dt + Ce^{-kt}T=e−kt∫kTe​(t)ektdt+Ce−kt.

    3. 3

      Definite-integral solution with T(0)=T0T(0) = T_0T(0)=T0​

      Redo the integral from 000 to ttt in the dummy variable t1t_1t1​, then set t=0t = 0t=0 and record the resulting value C=T0C = T_0C=T0​.

    4. 4

      Steady-state term and transient T0e−ktT_0 e^{-kt}T0​e−kt

      Name the two terms of T=e−kt∫0tkTe(t1)ekt1 dt1+T0e−ktT = e^{-kt}\int_0^t kT_e(t_1)e^{kt_1}\,dt_1 + T_0 e^{-kt}T=e−kt∫0t​kTe​(t1​)ekt1​dt1​+T0​e−kt and write the t→∞t \to \inftyt→∞ behaviour of each for k>0k > 0k>0.

    Attempt 1 of 2