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Differential Equations
The Geometric View of ODEs
01Direction Fields and the Geometric View of ODEs02Integral Curves and the Isocline Method03Perpendicular Isoclines: The Circles of y' = -x/y04Isocline Corridors and a Trap for Solutions05Existence and Uniqueness: One Curve Through a Point06Where Existence and Uniqueness FailProblem set0/10Problem set 20/10MIT problem set0/3Practice∞
Numerical Methods
01Euler's Method and Its Three Equations02Euler's Method by Hand: Building the Table03Convexity and the Sign of Euler's Error04First Order Error: Halve the Step, Halve the Error05Improved Euler (RK2): Averaging Two Slopes06Runge-Kutta 4 and the Price of Accuracy07Singular Points: Where Every Method FailsProblem set0/10Problem set 20/10MIT problem set0/1Practice∞
First-Order Linear Equations
01First Order Linear: Standard Form and the Sign of p02The Conduction-Diffusion Model: Newton's Law of Cooling03The Integrating Factor and the Four-Step Method04Integrating Factors: Two Mistakes and a Trick Question05Constant Coefficients: Steady State and TransientProblem set0/10Problem set 20/10MIT problem set0/1Practice∞

The Integrating Factor and the Four-Step Method

What forces the integrating factor to be $u = e^{\int p\,dx}$, and why does no arbitrary constant survive the derivation?


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Your summary note

    1. 1

      The integrating factor u=e∫p dxu=e^{\int p\,dx}u=e∫pdx

      Multiply y′+py=qy'+py=qy′+py=q by uuu, match (uy)′=uy′+u′y(uy)'=uy'+u'y(uy)′=uy′+u′y from the product rule to force u′=puu'=puu′=pu, separate variables, and state u=e∫p dxu=e^{\int p\,dx}u=e∫pdx with no arbitrary constant.

    2. 2

      The four steps of the method

      Write the four steps in order (standard linear form, the integrating factor, multiplying both sides, integration) and record the wrong-sign trap from reading ppp off y′=−py+qy'=-py+qy′=−py+q.

    3. 3

      The worked example xy′−y=x3xy'-y=x^3xy′−y=x3

      Carry it through: divide by xxx for standard form, simplify e−ln⁡xe^{-\ln x}e−lnx to 1/x1/x1/x, write (1xy)′=x\left(\frac{1}{x}y\right)'=x(x1​y)′=x and verify it with the product rule, then integrate to y=x32+cxy=\frac{x^3}{2}+cxy=2x3​+cx.

    Attempt 1 of 2