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First Order Linear: Standard Form and the Sign of p

Why does writing $y' = -py + q$ instead of $y' + py = q$ flip the sign of $p$ and change the solution's behavior entirely?


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Your summary note

    1. 1

      Linearity in yyy and y′y'y′, and homogeneity

      Write a(x)y′+b(x)y=c(x)a(x)y' + b(x)y = c(x)a(x)y′+b(x)y=c(x), set it beside the algebraic ay1+by2=ca y_1 + b y_2 = cay1​+by2​=c with y′y'y′ treated as a second variable, and record when the equation is homogeneous.

    2. 2

      Standard linear form y′+p(x)y=q(x)y' + p(x)y = q(x)y′+p(x)y=q(x)

      Divide a(x)y′+b(x)y=c(x)a(x)y' + b(x)y = c(x)a(x)y′+b(x)y=c(x) through by a(x)a(x)a(x), rename the coefficients p=b/ap = b/ap=b/a and q=c/aq = c/aq=c/a, and write out the resulting standard form.

    3. 3

      The sign trap in y′=−p(x)y+q(x)y' = -p(x)y + q(x)y′=−p(x)y+q(x)

      Record both rival forms side by side, note that y′+p(x)y=q(x)y' + p(x)y = q(x)y′+p(x)y=q(x) is the one used throughout, and state that a flipped sign of ppp produces solutions with totally different behavior.

    4. 4

      Always solvable, and where linear equations arise

      State that a first-order linear equation can always be solved, and list conduction-diffusion (temperature-concentration), mixing, radioactive decay, bank interest and motion problems as the models it governs.

    Attempt 1 of 2