Why does I + N always have a square root when N is nilpotent, and how does that give every invertible complex operator one?
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An operator with no square root
Write the proof by contradiction that on has no square root, noting that is not invertible.
Lemma: has a square root when is nilpotent
Write the guess , expand its square, and solve for , , one at a time.
Every invertible operator on a complex space has a square root
Write , build from a square root of and the lemma, glue the over the decomposition, and verify .
Where complex scalars are needed
Record the polar-form square root of a complex number and the operator multiplication by on , which has no square root.