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Single Variable Calculus
Differentiation
01The Derivative as the Slope of the Tangent Line02Secant Lines and the Limit Definition of the Derivative03Differentiating 1/x Straight From the Definition04Tangents to 1/x and the Triangle of Area 205Newton and Leibniz Notation, and the Power RuleProblem set0/10Problem set 20/10MIT problem set0/3
01The Derivative as an Instantaneous Rate of Change02Rates of Change Without Time: Gradient and Sensitivity03Easy Limits, 0/0, and One-Sided Limits04Continuity, Jumps, and Removable Discontinuities05Infinite Discontinuities: 1/x and Its Derivative06Differentiable Implies ContinuousProblem set0/10Problem set 20/10
01Two Kinds of Formula, and the Derivative of Sine02The Derivative of Cosine, and Two Limits at Zero03Bow and Bowstring: Proving the Two Trig Limits04Why the Trig Derivatives Hold Only in Radians05A Geometric Proof: Sine as a Height on the Circle06Finishing the Proof, and the Product and Quotient RulesProblem set0/10Problem set 20/10MIT problem set0/1
01Proving the Product Rule: Change One Factor at a Time02The Quotient Rule, and the Power Rule for Negative Exponents03The Chain Rule: Differentiating a Function of a Function04Higher Derivatives: The Sine Cycle and Three Notations05The nth Derivative of xⁿ Is n Factorial, by InductionProblem set0/10Problem set 20/10MIT problem set0/2
01The Power Rule for Rational Exponents02The Slope of a Circle, Two Ways03Implicit Differentiation of a Quartic Curve04Inverse Functions and the Reflection Across y = x05Derivatives of the Arctangent and ArcsineProblem set0/10Problem set 20/10MIT problem set0/1
01The Derivative of aˣ and the Mystery Number M(a)02Defining e by Slope One, and the Derivative of ln x03M(a) = ln a: Differentiating aˣ and xˣ04Why (1 + 1/n)ⁿ Approaches eProblem set0/10Problem set 20/10MIT problem set0/1
Applications of Differentiation
01Linear Approximation: A Curve Is Its Tangent Line02Five Linear Approximations at Zero03Combining Approximations, from Algebra to GPS Clocks04Quadratic Approximation: The Best-Fit ParabolaProblem set0/10Problem set 20/10MIT problem set0/1
01Linear Approximation as a Proportionality Rule02Quadratic Approximation: Why the ½, and Products03Curve Sketching: The Sign of f′ and Critical Points04Curve Sketching: Ends, Concavity and InflectionProblem set0/10Problem set 20/10MIT problem set0/1
01Sketching Without Critical Points: (x+1)/(x+2)02A Five-Step Curve-Sketching Scheme, Applied to x / ln x03x / ln x: Inflection Point and Where Max and Min Can OccurProblem set0/10Problem set 20/10
01Two Squares From One Wire: The Critical Point Gives the Least Area02The Open Box of Fixed Volume: Least Material When x = 2y03Related Rates: The Police Radar and the Conical TankProblem set0/10Problem set 20/10MIT problem set0/4
01The Hanging Ring: Why the String Makes Equal Angles02Newton's Method: Tangent Lines That Find the Square Root of Five03Why Newton's Method Doubles Its Digits, and How It Fails04The Mean Value Theorem: Somewhere You Hit Your Average Speed05Positive Derivative Means Increasing: Proving eˣ Exceeds 1 + xProblem set0/10Problem set 20/10MIT problem set0/2
Integration
01Differentials: dy = f′(x) dx and the Cube Root of 64.102Antiderivatives Differ Only by a Constant03Integration by Substitution and Advanced GuessingProblem set0/10Problem set 20/10MIT problem set0/1
01Separation of Variables: dy/dx = −xy and the Bell Curve02General Solutions: Signs, Constants and Initial Conditions03Orthogonal Trajectories: Parabolas and Crossing EllipsesProblem set0/10Problem set 20/10MIT problem set0/1
01The Definite Integral: Area as a Limit of Rectangle Sums02Area Under y = x²: Squeezing the Sum of Squares03Sigma Notation and the Area Pattern: b, b²/2, b³/304Riemann Sums: the Definite Integral and a Year of LoansProblem set0/10Problem set 20/10MIT problem set0/1
01The Fundamental Theorem of Calculus: Area in One Line02Net Change and Signed Area: Integrating Velocity03Six Rules for Definite Integrals and Bounds on eᵇ04Substitution in Definite Integrals: Change the LimitsProblem set0/10Problem set 20/10MIT problem set0/1

The Open Box of Fixed Volume: Least Material When x = 2y

How does a fixed volume collapse the open box to one variable, and why is the 2:1 shape a better answer than the dimensions?


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Your summary note

    1. 1

      Eliminating a variable with the constraint V=x2yV = x^2 yV=x2y

      Write V=x2yV = x^2 yV=x2y and A=x2+4xyA = x^2 + 4xyA=x2+4xy for the square-based open box, solve for yyy, and derive A=x2+4VxA = x^2 + \frac{4V}{x}A=x2+x4V​ and the critical point x=21/3V1/3x = 2^{1/3}V^{1/3}x=21/3V1/3.

    2. 2

      An infinite end: A→∞A \to \inftyA→∞ at both ends

      Justify the range 0<x<∞0 < x < \infty0<x<∞, take the limit of AAA at each end, conclude the single critical point is the minimum, and add the check A′′=2+8Vx3>0A'' = 2 + \frac{8V}{x^3} > 0A′′=2+x38V​>0.

    3. 3

      Dimensionless answers AV2/3\frac{A}{V^{2/3}}V2/3A​ and xy\frac{x}{y}yx​

      Compute y=2−2/3V1/3y = 2^{-2/3}V^{1/3}y=2−2/3V1/3 and the minimum area, then reduce them to the scaling law AV2/3=3⋅22/3\frac{A}{V^{2/3}} = 3 \cdot 2^{2/3}V2/3A​=3⋅22/3 and the scale-free 2:12:12:1 shape xy=2\frac{x}{y} = 2yx​=2.

    4. 4

      Implicit differentiation route to x=2yx = 2yx=2y

      Differentiate the constraint to get y′=−2yxy' = -\frac{2y}{x}y′=−x2y​, substitute into dAdx=2x+4y+4xy′\frac{dA}{dx} = 2x + 4y + 4xy'dxdA​=2x+4y+4xy′ to reach x=2yx = 2yx=2y, and record that this alone does not classify the critical point.

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