How does a fixed volume collapse the open box to one variable, and why is the 2:1 shape a better answer than the dimensions?
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Eliminating a variable with the constraint
Write and for the square-based open box, solve for , and derive and the critical point .
An infinite end: at both ends
Justify the range , take the limit of at each end, conclude the single critical point is the minimum, and add the check .
Dimensionless answers and
Compute and the minimum area, then reduce them to the scaling law and the scale-free shape .
Implicit differentiation route to
Differentiate the constraint to get , substitute into to reach , and record that this alone does not classify the critical point.