Why can no parallelepiped with given edge lengths beat the box, and how does QR factorization turn that into a bound on |det A|?
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Reducing to the QR factorization
Dispose of the non-invertible case, then write with unitary and upper triangular with positive diagonal.
The chain of equalities and one inequality
Write the full chain from to , marking the single inequality and the step where preserves norms.
The geometric meaning
Describe the image of the unit cube as the parallelepiped spanned by the columns and state which shape of parallelepiped has the largest volume for given edge lengths.