How do the three possible remainders on division by 3 become the three cases of a proof that 3 divides n³ − n?
Loading…
Remainders as the cases of a proof
State that dividing an arbitrary by gives with , and that dividing by would give four cases.
The three cases for
Substitute , and into , expanding each cube in full and factoring the result as times an integer.
Closing the proof by cases
Write the concluding sentence that the three cases exhaust every integer, so for all integers .