How do sign cases prove |xy| = |x||y| and the Triangle Inequality |x + y| ≤ |x| + |y|?
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if and only if
For , prove both conditionals of the biconditional, each with the cases and .
in four sign cases
Prove the product rule with one case for each combination of signs of and , noting the zero values in the mixed-sign cases.
The Triangle Inequality
First prove and for every real , then prove the inequality with the cases and .