Why does proving two sets equal take two subset proofs, and how does negating x ∈ A − B unlock A − (A − B) = A ∩ B?
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Set equality as two subset proofs
State that if and only if and , and record that each inclusion is proved by choosing an arbitrary element of one set.
Negating membership in
Write the condition for , then write its negation or as the statement each direction of the proof relies on.
The two inclusions for
Write out both element-chasing proofs, and , then the closing sentence that combines them into the equality.
The worked example
Prove both inclusions from the definitions of set difference and complement, carrying each chosen element through to membership in the other set.