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Multivariable Calculus
Vectors and Dot Products
01Vectors, Components, and Length in Space02Scaling and Adding Vectors: The Parallelogram Rule03The Dot Product and the Law of Cosines04Finding Angles in Space With the Dot Product05The Perpendicularity Test and the Normal Vector to a PlaneProblem set0/10Problem set 20/10MIT problem set0/2Practice∞
Determinants and the Cross Product
01The Component of a Vector Along Any Unit Direction02The 2x2 Determinant and the Area of a Parallelogram03The 3x3 Determinant and the Volume of a Box04The Cross Product and the Right-Hand Rule05The Triple Product and the Volume of a ParallelepipedProblem set0/10Problem set 20/10MIT problem set0/2Practice∞
Matrices and Inverse Matrices
01Why Swapping a Cross Product Flips Its Sign02The Equation of a Plane Through Three Points03Matrix Multiplication: Rows Dotted With Columns04Matrices as Transformations: Identity and Rotation05The Inverse Matrix and Solving AX = B06Computing a 3x3 Inverse: Minors, Cofactors, AdjointProblem set0/10Problem set 20/10MIT problem set0/2Practice∞
Planes and Square Systems
01Planes From a Point and a Normal Vector02Reading the Normal Vector Off a Plane Equation03Three Planes, One Point: Solving a 3x3 System04Invertibility, det A, and the Homogeneous System05When det A = 0: Coplanar Normals and a Line of SolutionsProblem set0/10Problem set 20/10Practice∞

Finding Angles in Space With the Dot Product

How do one dot product and two lengths pin down an angle in space, and what does the sign alone already reveal?


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Your summary note

    1. 1

      Angle formula cos⁡θ=A⃗⋅B⃗∣A⃗∣ ∣B⃗∣\cos\theta = \frac{\vec{A}\cdot\vec{B}}{|\vec{A}|\,|\vec{B}|}cosθ=∣A∣∣B∣A⋅B​

      Rearrange the dot product theorem to isolate the cosine, and note that every quantity on the right is computable from components.

    2. 2

      Worked example: angle at PPP in a triangle

      Using P=(1,0,0)P=(1,0,0)P=(1,0,0), Q=(0,1,0)Q=(0,1,0)Q=(0,1,0), R=(0,0,2)R=(0,0,2)R=(0,0,2), build PQ→\overrightarrow{PQ}PQ​ and PR→\overrightarrow{PR}PR, compute their lengths and dot product, then take the inverse cosine to get θ≈71.5°\theta\approx 71.5°θ≈71.5°.

    3. 3

      Sign of the dot product classifies the angle

      Record that positive means acute, zero means perpendicular, and negative means obtuse, since the positive lengths make the dot product's sign match the sign of cos⁡θ\cos\thetacosθ.

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