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Multivariable Calculus
Vectors and Dot Products
01Vectors, Components, and Length in Space02Scaling and Adding Vectors: The Parallelogram Rule03The Dot Product and the Law of Cosines04Finding Angles in Space With the Dot Product05The Perpendicularity Test and the Normal Vector to a PlaneProblem set0/10Problem set 20/10MIT problem set0/2Practice∞
Determinants and the Cross Product
01The Component of a Vector Along Any Unit Direction02The 2x2 Determinant and the Area of a Parallelogram03The 3x3 Determinant and the Volume of a Box04The Cross Product and the Right-Hand Rule05The Triple Product and the Volume of a ParallelepipedProblem set0/10Problem set 20/10MIT problem set0/2Practice∞
Matrices and Inverse Matrices
01Why Swapping a Cross Product Flips Its Sign02The Equation of a Plane Through Three Points03Matrix Multiplication: Rows Dotted With Columns04Matrices as Transformations: Identity and Rotation05The Inverse Matrix and Solving AX = B06Computing a 3x3 Inverse: Minors, Cofactors, AdjointProblem set0/10Problem set 20/10MIT problem set0/2Practice∞
Planes and Square Systems
01Planes From a Point and a Normal Vector02Reading the Normal Vector Off a Plane Equation03Three Planes, One Point: Solving a 3x3 System04Invertibility, det A, and the Homogeneous System05When det A = 0: Coplanar Normals and a Line of SolutionsProblem set0/10Problem set 20/10Practice∞

The Triple Product and the Volume of a Parallelepiped

Why does building a volume as base times height collapse into A dot (B cross C), the very determinant you were trying to avoid?


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Your summary note

    1. 1

      Volume as base area times height

      Derive volume=∣B⃗×C⃗∣(A⃗⋅n^)\text{volume} = |\vec{B} \times \vec{C}|\left(\vec{A} \cdot \hat{n}\right)volume=∣B×C∣(A⋅n^) using base area ∣B⃗×C⃗∣|\vec{B} \times \vec{C}|∣B×C∣, height A⃗⋅n^\vec{A} \cdot \hat{n}A⋅n^, and n^=(B⃗×C⃗)/∣B⃗×C⃗∣\hat{n} = (\vec{B} \times \vec{C})/|\vec{B} \times \vec{C}|n^=(B×C)/∣B×C∣, then cancel to get A⃗⋅(B⃗×C⃗)\vec{A} \cdot (\vec{B} \times \vec{C})A⋅(B×C).

    2. 2

      Order and parentheses in the triple product

      Record that the cross product must be computed first and note what goes wrong if A⃗⋅B⃗\vec{A} \cdot \vec{B}A⋅B is done first.

    3. 3

      Identity det⁡(A⃗,B⃗,C⃗)=A⃗⋅(B⃗×C⃗)\det(\vec{A}, \vec{B}, \vec{C}) = \vec{A} \cdot (\vec{B} \times \vec{C})det(A,B,C)=A⋅(B×C)

      Write the first-row expansion of the determinant, write A⃗⋅(B⃗×C⃗)\vec{A} \cdot (\vec{B} \times \vec{C})A⋅(B×C) using the i,j,ki, j, ki,j,k components of B⃗×C⃗\vec{B} \times \vec{C}B×C as the three 2×22 \times 22×2 minors, and match the two expressions term by term.

    Attempt 1 of 2