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Multivariable Calculus
Vectors and Dot Products
01Vectors, Components, and Length in Space02Scaling and Adding Vectors: The Parallelogram Rule03The Dot Product and the Law of Cosines04Finding Angles in Space With the Dot Product05The Perpendicularity Test and the Normal Vector to a PlaneProblem set0/10Problem set 20/10MIT problem set0/2Practice∞
Determinants and the Cross Product
01The Component of a Vector Along Any Unit Direction02The 2x2 Determinant and the Area of a Parallelogram03The 3x3 Determinant and the Volume of a Box04The Cross Product and the Right-Hand Rule05The Triple Product and the Volume of a ParallelepipedProblem set0/10Problem set 20/10MIT problem set0/2Practice∞
Matrices and Inverse Matrices
01Why Swapping a Cross Product Flips Its Sign02The Equation of a Plane Through Three Points03Matrix Multiplication: Rows Dotted With Columns04Matrices as Transformations: Identity and Rotation05The Inverse Matrix and Solving AX = B06Computing a 3x3 Inverse: Minors, Cofactors, AdjointProblem set0/10Problem set 20/10MIT problem set0/2Practice∞
Planes and Square Systems
01Planes From a Point and a Normal Vector02Reading the Normal Vector Off a Plane Equation03Three Planes, One Point: Solving a 3x3 System04Invertibility, det A, and the Homogeneous System05When det A = 0: Coplanar Normals and a Line of SolutionsProblem set0/10Problem set 20/10Practice∞

Why Swapping a Cross Product Flips Its Sign

Why does swapping the two vectors in a cross product cost a minus sign, and how does a determinant that is not really a determinant remember it?


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    1. 1

      The symbolic 3×33\times 33×3 determinant for A⃗×B⃗\vec{A}\times\vec{B}A×B

      Write the array with i^,j^,k^\hat{i},\hat{j},\hat{k}i^,j^​,k^ in the top row, record that it is a memory device rather than a true determinant, and expand along that row into the componentwise formula.

    2. 2

      Length as parallelogram area, direction by the right-hand rule

      State that ∣A⃗×B⃗∣|\vec{A}\times\vec{B}|∣A×B∣ is the area of the parallelogram with sides A⃗\vec{A}A and B⃗\vec{B}B, and record the right-hand rule that picks one of the two perpendicular directions.

    3. 3

      Anti-commutativity A⃗×B⃗=− B⃗×A⃗\vec{A}\times\vec{B}=-\,\vec{B}\times\vec{A}A×B=−B×A

      Write the identity, reproduce the right-hand-rule argument with the two vectors exchanged, and check the sign on the i^\hat{i}i^ component a2b3−a3b2a_2b_3-a_3b_2a2​b3​−a3​b2​.

    4. 4

      The special case A⃗×A⃗=0⃗\vec{A}\times\vec{A}=\vec{0}A×A=0

      Record the result with both arguments: the componentwise formula evaluated on A⃗\vec{A}A twice, and the flat parallelogram spanned by A⃗\vec{A}A with itself.

    Attempt 1 of 2