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Multivariable Calculus
Vectors and Dot Products
01Vectors, Components, and Length in Space02Scaling and Adding Vectors: The Parallelogram Rule03The Dot Product and the Law of Cosines04Finding Angles in Space With the Dot Product05The Perpendicularity Test and the Normal Vector to a PlaneProblem set0/10Problem set 20/10MIT problem set0/2Practice∞
Determinants and the Cross Product
01The Component of a Vector Along Any Unit Direction02The 2x2 Determinant and the Area of a Parallelogram03The 3x3 Determinant and the Volume of a Box04The Cross Product and the Right-Hand Rule05The Triple Product and the Volume of a ParallelepipedProblem set0/10Problem set 20/10MIT problem set0/2Practice∞
Matrices and Inverse Matrices
01Why Swapping a Cross Product Flips Its Sign02The Equation of a Plane Through Three Points03Matrix Multiplication: Rows Dotted With Columns04Matrices as Transformations: Identity and Rotation05The Inverse Matrix and Solving AX = B06Computing a 3x3 Inverse: Minors, Cofactors, AdjointProblem set0/10Problem set 20/10MIT problem set0/2Practice∞
Planes and Square Systems
01Planes From a Point and a Normal Vector02Reading the Normal Vector Off a Plane Equation03Three Planes, One Point: Solving a 3x3 System04Invertibility, det A, and the Homogeneous System05When det A = 0: Coplanar Normals and a Line of SolutionsProblem set0/10Problem set 20/10Practice∞

Computing a 3x3 Inverse: Minors, Cofactors, Adjoint

What do minors, a checkerboard of signs, a transpose, and one division by the determinant do to hand you A inverse?


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    1. 1

      The four steps behind A−1=1det⁡(A)adj⁡(A)A^{-1} = \frac{1}{\det(A)}\operatorname{adj}(A)A−1=det(A)1​adj(A)

      Write the formula down, name the four steps in order, and build the matrix of minors of the worked 3×33 \times 33×3 example by deleting each entry's row and column.

    2. 2

      The checkerboard sign rule for cofactors

      Draw the + − ++\,-\,++−+ checkerboard, record that a plus leaves an entry alone and a minus flips its sign rather than forcing a positive or negative, and write out the cofactor matrix.

    3. 3

      Transposing to adj⁡(A)\operatorname{adj}(A)adj(A), then dividing by det⁡(A)\det(A)det(A)

      Define the adjoint as the transpose of the cofactor matrix, note that the divisor is det⁡(A)\det(A)det(A) and never the determinant of the adjoint, and finish the worked example.

    4. 4

      The two uses of A−1A^{-1}A−1

      Record that A−1A^{-1}A−1 reverses the change of variables as X=A−1UX = A^{-1}UX=A−1U, and that it solves a linear system AX=BAX = BAX=B as X=A−1BX = A^{-1}BX=A−1B.

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