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Multivariable Calculus
Vectors and Dot Products
01Vectors, Components, and Length in Space02Scaling and Adding Vectors: The Parallelogram Rule03The Dot Product and the Law of Cosines04Finding Angles in Space With the Dot Product05The Perpendicularity Test and the Normal Vector to a PlaneProblem set0/10Problem set 20/10MIT problem set0/2Practice∞
Determinants and the Cross Product
01The Component of a Vector Along Any Unit Direction02The 2x2 Determinant and the Area of a Parallelogram03The 3x3 Determinant and the Volume of a Box04The Cross Product and the Right-Hand Rule05The Triple Product and the Volume of a ParallelepipedProblem set0/10Problem set 20/10MIT problem set0/2Practice∞
Matrices and Inverse Matrices
01Why Swapping a Cross Product Flips Its Sign02The Equation of a Plane Through Three Points03Matrix Multiplication: Rows Dotted With Columns04Matrices as Transformations: Identity and Rotation05The Inverse Matrix and Solving AX = B06Computing a 3x3 Inverse: Minors, Cofactors, AdjointProblem set0/10Problem set 20/10MIT problem set0/2Practice∞
Planes and Square Systems
01Planes From a Point and a Normal Vector02Reading the Normal Vector Off a Plane Equation03Three Planes, One Point: Solving a 3x3 System04Invertibility, det A, and the Homogeneous System05When det A = 0: Coplanar Normals and a Line of SolutionsProblem set0/10Problem set 20/10Practice∞

The Equation of a Plane Through Three Points

How can flattening a box and demanding a right angle turn out to be the very same equation for a plane through three points?


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Your summary note

    1. 1

      The flattened parallelepiped test

      State that PPP lies in the plane exactly when the box built on P1P→\overrightarrow{P_1P}P1​P​, P1P2→\overrightarrow{P_1P_2}P1​P2​​ and P1P3→\overrightarrow{P_1P_3}P1​P3​​ is squashed flat, and expand det⁡(P1P→,P1P2→,P1P3→)=0\det(\overrightarrow{P_1P},\overrightarrow{P_1P_2},\overrightarrow{P_1P_3})=0det(P1​P​,P1​P2​​,P1​P3​​)=0 into an equation in xxx, yyy, zzz.

    2. 2

      The normal vector condition P1P→⋅N⃗=0\overrightarrow{P_1P}\cdot\vec{N}=0P1​P​⋅N=0

      Define N⃗\vec{N}N as a vector perpendicular to the plane, state that PPP lies in the plane exactly when P1P→⊥N⃗\overrightarrow{P_1P}\perp\vec{N}P1​P​⊥N, and write that condition out in xxx, yyy, zzz.

    3. 3

      The normal vector from the cross product

      Record N⃗=P1P2→×P1P3→\vec{N}=\overrightarrow{P_1P_2}\times\overrightarrow{P_1P_3}N=P1​P2​​×P1​P3​​, note that the reversed order gives the opposite vector, and state that every nonzero multiple of N⃗\vec{N}N is again a normal vector.

    4. 4

      The triple product identifying the two methods

      Write P1P→⋅(P1P2→×P1P3→)\overrightarrow{P_1P}\cdot(\overrightarrow{P_1P_2}\times\overrightarrow{P_1P_3})P1​P​⋅(P1​P2​​×P1​P3​​), identify it as the triple product equal to the determinant, and record that the two quantities always agree and vanish exactly for PPP in the plane.

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