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When f′ is never zero, how do one-sided limits at x = −2 and the ends at ±∞ still pin down the whole graph of (x+1)/(x+2)?
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The undefined point and the ends give the asymptotes
Compute and by tracking the sign of the denominator near , and find by dividing numerator and denominator by .
Increasing on each branch, never for all
Sketch both branches between the asymptotes and , rewrite to confirm , and state the two increasing intervals separately.
Concavity from
Derive , record its sign on each side of (concave down to the right, concave up to the left), and note that this rules out a wiggle in either branch.
implies increasing, but not conversely
Write the one-way implication and give an increasing cubic such as , whose derivative vanishes at a point, as the counterexample to the converse.