Why does $v = 1/y$ make $y' = y/x - y^2$ linear, and why must $v$ become one fraction before you turn it back into $y$?
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Recognizing and reducing to a linear equation
Record the concealed form , divide by , and use with from the chain rule to reach .
The integrating factor for
Compute , multiply through to , check that the left side is , and integrate to .
Converting back to
Combine into the single fraction before inverting, rename as , and record that the constant is not additive, so an initial condition is fitted from this final form.