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Differential Equations
The Geometric View of ODEs
01Direction Fields and the Geometric View of ODEs02Integral Curves and the Isocline Method03Perpendicular Isoclines: The Circles of y' = -x/y04Isocline Corridors and a Trap for Solutions05Existence and Uniqueness: One Curve Through a Point06Where Existence and Uniqueness FailProblem set0/10Problem set 20/10MIT problem set0/3
Numerical Methods
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First-Order Linear Equations
01First Order Linear: Standard Form and the Sign of p02The Conduction-Diffusion Model: Newton's Law of Cooling03The Integrating Factor and the Four-Step Method04Integrating Factors: Two Mistakes and a Trick Question05Constant Coefficients: Steady State and TransientProblem set0/10Problem set 20/10MIT problem set0/1
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Autonomous Equations
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Complex Numbers
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Input and Response
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01Cartesian Method: Rationalise, Then Take the Real Part02The Sinusoidal Identity and Its Right Triangle03Three Proofs of the Sinusoidal Identity04The Mixing Tank: Salt Balance and k = r/V05RC Circuits, Decay Chains and Negative kProblem set0/10Problem set 20/10MIT problem set0/2
Second-Order Linear Equations
01Second-Order Linear ODEs and the Spring–Mass–Dashpot02The Characteristic Equation and Overdamped Motion03Complex Roots a ± bi and Underdamped Oscillation04Critical Damping and Reduction of Order: t e^(−at)Problem set0/10Problem set 20/10MIT problem set0/2

Critical Damping and Reduction of Order: t e^(−at)

When the characteristic equation has a double root, where does the missing second solution $t\,e^{-at}$ come from?


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Your summary note

    1. 1

      Critical damping as the double-root case

      Write the characteristic equation (r+a)2=r2+2ar+a2=0(r+a)^2 = r^2 + 2ar + a^2 = 0(r+a)2=r2+2ar+a2=0 with a>0a > 0a>0, the resulting equation y′′+2ay′+a2y=0y'' + 2ay' + a^2 y = 0y′′+2ay′+a2y=0, and the single solution e−ate^{-at}e−at it gives.

    2. 2

      Reduction of order: seek y=y1uy = y_1 uy=y1​u

      State the method for y′′+py′+qy=0y'' + py' + qy = 0y′′+py′+qy=0, with ppp and qqq possibly functions of ttt: given one solution y1y_1y1​, seek a second solution y=y1uy = y_1 uy=y1​u.

    3. 3

      The column computation giving e−atu′′=0e^{-at}u'' = 0e−atu′′=0

      For y=e−atuy = e^{-at}uy=e−atu, list yyy, y′y'y′, y′′y''y′′ in a column with multipliers a2a^2a2, 2a2a2a, 111, add column by column to reach e−atu′′=0e^{-at}u'' = 0e−atu′′=0, and conclude u=c1t+c2u = c_1 t + c_2u=c1​t+c2​.

    4. 4

      The general solution y=(c1+c2t)e−aty = (c_1 + c_2 t)e^{-at}y=(c1​+c2​t)e−at

      Record the two independent solutions e−ate^{-at}e−at and te−atte^{-at}te−at and combine them into the general solution of the critically damped equation.

    Attempt 1 of 2