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Input and Response
01Steady-State and Transient Solutions of y' + ky = q(t)02Input, Response and the Superposition Principle03Solving y' + ky = k cos ωt by Complexification04Amplitude and Phase Lag of a Sinusoidal ResponseProblem set0/10Problem set 20/10MIT problem set0/2
01Cartesian Method: Rationalise, Then Take the Real Part02The Sinusoidal Identity and Its Right Triangle03Three Proofs of the Sinusoidal Identity04The Mixing Tank: Salt Balance and k = r/V05RC Circuits, Decay Chains and Negative kProblem set0/10Problem set 20/10MIT problem set0/2
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Amplitude and Phase Lag of a Sinusoidal Response

How do the amplitude and phase lag of the response to $\cos\omega t$ depend on $\omega/k$, and why does a larger $k$ track the input better?


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Your summary note

    1. 1

      Modulus and argument of a reciprocal 1/α1/\alpha1/α

      Derive ∣1/α∣=1/∣α∣|1/\alpha| = 1/|\alpha|∣1/α∣=1/∣α∣ and arg⁡(1/α)=−arg⁡α\arg(1/\alpha) = -\arg\alphaarg(1/α)=−argα starting from 1α⋅α=1\frac{1}{\alpha} \cdot \alpha = 1α1​⋅α=1.

    2. 2

      The real response Acos⁡(ωt−ϕ)A\cos(\omega t - \phi)Acos(ωt−ϕ)

      Draw the triangle for 1+i(ω/k)1 + i(\omega/k)1+i(ω/k), write its reciprocal as Ae−iϕAe^{-i\phi}Ae−iϕ, and carry the real part through to y1=cos⁡(ωt−ϕ)1+(ω/k)2y_1 = \frac{\cos(\omega t - \phi)}{\sqrt{1 + (\omega/k)^2}}y1​=1+(ω/k)2​cos(ωt−ϕ)​ with ϕ=tan⁡−1(ω/k)\phi = \tan^{-1}(\omega/k)ϕ=tan−1(ω/k).

    3. 3

      The phase lag ϕ\phiϕ as an angle on the cycle

      Sketch cos⁡ωt\cos\omega tcosωt and cos⁡(ωt−π/2)\cos(\omega t - \pi/2)cos(ωt−π/2), record sin⁡ωt=cos⁡(ωt−π/2)\sin\omega t = \cos(\omega t - \pi/2)sinωt=cos(ωt−π/2), and state that the corresponding time shift on the ttt-axis is ϕ/ω\phi/\omegaϕ/ω.

    4. 4

      Effect of raising the conductivity kkk

      Use the triangle and the formula for AAA to show that increasing kkk raises the amplitude toward 1 and lowers the phase lag, and record what this means for the temperature model.

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