Why is $a\cos\theta + b\sin\theta$ secretly one shifted cosine, and how does a right triangle with legs $a$ and $b$ hand you its amplitude and phase?
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The identity
State the identity and record its requirement that the cosine and sine terms share the same angle, which in applications means the same frequency .
and from the right triangle
Draw the triangle with legs and , label the hypotenuse and the angle opposite , and write and .
Converting the Cartesian answer to amplitude-phase form
Apply the triangle with legs and to , carry out the cancellation with the front factor, and arrive at the polar-method formula.
Two parameters in each form
Record that and are equally general, and state what a messy answer really is: a pure oscillation, rescaled and shifted.