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Differential Equations
The Geometric View of ODEs
01Direction Fields and the Geometric View of ODEs02Integral Curves and the Isocline Method03Perpendicular Isoclines: The Circles of y' = -x/y04Isocline Corridors and a Trap for Solutions05Existence and Uniqueness: One Curve Through a Point06Where Existence and Uniqueness FailProblem set0/10Problem set 20/10MIT problem set0/3
Numerical Methods
01Euler's Method and Its Three Equations02Euler's Method by Hand: Building the Table03Convexity and the Sign of Euler's Error04First Order Error: Halve the Step, Halve the Error05Improved Euler (RK2): Averaging Two Slopes06Runge-Kutta 4 and the Price of Accuracy07Singular Points: Where Every Method FailsProblem set0/10Problem set 20/10MIT problem set0/1
First-Order Linear Equations
01First Order Linear: Standard Form and the Sign of p02The Conduction-Diffusion Model: Newton's Law of Cooling03The Integrating Factor and the Four-Step Method04Integrating Factors: Two Mistakes and a Trick Question05Constant Coefficients: Steady State and TransientProblem set0/10Problem set 20/10MIT problem set0/1
Substitution Methods
01Scaling a First Order ODE: The Fourth-Power Cooling Law02The Bernoulli Equation and the Substitution v = y^(1-n)03A Worked Bernoulli Example: The Substitution v = 1/y04Homogeneous Equations: The Zoom Test and y = zx05Modelling the Lighthouse Chase: A 45-Degree Heading06The Boat's Path: A Logarithmic Spiral in Polar CoordinatesProblem set0/10Problem set 20/10
Autonomous Equations
01Autonomous Equations and Time-Translation Invariance02Critical Points: Constant Solutions as Barriers03The Embezzler Model dy/dt = ry - w: One Unstable Balance04The Logistic Equation: Carrying Capacity Without Solving05Stable, Unstable and Semi-Stable Critical Points06Maximum Sustainable Harvest: Why h = a^2/4bProblem set0/10Problem set 20/10MIT problem set0/3
Complex Numbers
01Complex Division, Polar Form and the Definition of e^(iθ)02Why e^(iθ) Earns Its Name: Multiply Moduli, Add Angles03Integrating e^(-x) cos x by Complexifying04The nth Roots of Unity: Zeta on the Unit CircleProblem set0/10Problem set 20/10MIT problem set0/4
Input and Response
01Steady-State and Transient Solutions of y' + ky = q(t)02Input, Response and the Superposition Principle03Solving y' + ky = k cos ωt by Complexification04Amplitude and Phase Lag of a Sinusoidal ResponseProblem set0/10Problem set 20/10MIT problem set0/2
01Cartesian Method: Rationalise, Then Take the Real Part02The Sinusoidal Identity and Its Right Triangle03Three Proofs of the Sinusoidal Identity04The Mixing Tank: Salt Balance and k = r/V05RC Circuits, Decay Chains and Negative kProblem set0/10Problem set 20/10MIT problem set0/2
Second-Order Linear Equations
01Second-Order Linear ODEs and the Spring–Mass–Dashpot02The Characteristic Equation and Overdamped Motion03Complex Roots a ± bi and Underdamped Oscillation04Critical Damping and Reduction of Order: t e^(−at)Problem set0/10Problem set 20/10MIT problem set0/2

Scaling a First Order ODE: The Fourth-Power Cooling Law

Why does rescaling temperature by $M$ strip a constant out of $dT/dt = k(M^4 - T^4)$, and what units does the leftover constant carry?


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Your summary note

    1. 1

      Separable and linear: the only two general methods

      State that separable and first-order linear equations are essentially the only kinds that can always be solved, and that most other solvable equations are reduced to one of them by changing variables.

    2. 2

      Scaling x1=x/ax_1 = x/ax1​=x/a, y1=y/by_1 = y/by1​=y/b and its uses

      Write the scaling change of variables with constants aaa and bbb, and list its three purposes: changing units, making the variables dimensionless, and reducing the number of constants or simplifying them.

    3. 3

      Substituting T=MT1T = MT_1T=MT1​ into dTdt=k(M4−T4)\frac{dT}{dt} = k(M^4 - T^4)dtdT​=k(M4−T4)

      Define T1=T/MT_1 = T/MT1​=T/M, record that the substitution itself uses the inverse form T=MT1T = MT_1T=MT1​, and carry the algebra through to dT1dt=kM3(1−T14)\frac{dT_1}{dt} = kM^3(1 - T_1^4)dtdT1​​=kM3(1−T14​).

    4. 4

      Lumping constants into k1=kM3k_1 = kM^3k1​=kM3

      Rename kM3kM^3kM3 as k1k_1k1​ to reach dT1dt=k1(1−T14)\frac{dT_1}{dt} = k_1(1 - T_1^4)dtdT1​​=k1​(1−T14​), and record the three gains: a dimensionless T1T_1T1​, one less constant, and k1k_1k1​ in units of inverse time only.

    Attempt 1 of 2