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Multivariable Calculus
Vectors and Dot Products
01Vectors, Components, and Length in Space02Scaling and Adding Vectors: The Parallelogram Rule03The Dot Product and the Law of Cosines04Finding Angles in Space With the Dot Product05The Perpendicularity Test and the Normal Vector to a PlaneProblem set0/10Problem set 20/10MIT problem set0/2
Determinants and the Cross Product
01The Component of a Vector Along Any Unit Direction02The 2x2 Determinant and the Area of a Parallelogram03The 3x3 Determinant and the Volume of a Box04The Cross Product and the Right-Hand Rule05The Triple Product and the Volume of a ParallelepipedProblem set0/10Problem set 20/10MIT problem set0/2
Matrices and Inverse Matrices
01Why Swapping a Cross Product Flips Its Sign02The Equation of a Plane Through Three Points03Matrix Multiplication: Rows Dotted With Columns04Matrices as Transformations: Identity and Rotation05The Inverse Matrix and Solving AX = B06Computing a 3x3 Inverse: Minors, Cofactors, AdjointProblem set0/10Problem set 20/10MIT problem set0/2
Planes and Square Systems
01Planes From a Point and a Normal Vector02Reading the Normal Vector Off a Plane Equation03Three Planes, One Point: Solving a 3x3 System04Invertibility, det A, and the Homogeneous System05When det A = 0: Coplanar Normals and a Line of SolutionsProblem set0/10Problem set 20/10
Parametric Lines and Curves
01Parametric Equations of a Line Through Two Points02Where a Line Meets a Plane, and When It Never Does03The Cycloid: Choosing a Parameter That Is Not Time04Deriving the Cycloid's Equations From Three Vectors05Is the Cycloid's Bottom a Corner? Taylor Expansion Finds a CuspProblem set0/10Problem set 20/10MIT problem set0/2
Velocity and Kepler's Law
01Velocity and Speed on the Cycloid: Why the Point Stops Dead02Acceleration Is a Vector: Turning at Constant Speed Still Counts03Arc Length and the Unit Tangent: v = T̂ ds/dt04Equal Areas in Equal Times: Kepler's Second Law and |r × v|05Kepler's Second Law Means the Force Is CentralProblem set0/10Problem set 20/10MIT problem set0/1
Functions of Several Variables
01Functions of Two Variables: Graphs as Surfaces, Built from Slices02Level Curves and Contour Plots: A Surface Drawn as a Flat Map03Reading Contour Plots: Domes, Bowls, Saddles and Mountain Passes04Partial Derivatives: Change One Variable, Hold the Other FixedProblem set0/10Problem set 20/10MIT problem set0/2
Optimization and Least Squares
01Approximation Formula: Changes in x and y Add, via the Tangent Plane02Critical Points: Where Both Partial Derivatives Are Zero03Minimum, Maximum or Saddle Point? Classifying by Completing the Square04Least Squares: The Best-Fit Line as a Minimization in a and b05Solving Least Squares: Best-Fit Lines, Exponentials and ParabolasProblem set0/10Problem set 20/10MIT problem set0/3
The Second Derivative Test
01Quadratic Critical Points: The Sign of 4ac − b² Decides02The Second Derivative Test: Classifying by the Sign of AC − B²03Global Min and Max of x + y + 1/(xy): Boundary and InfinityProblem set0/10Problem set 20/10MIT problem set0/1
Differentials and the Chain Rule
01The Total Differential: Why df Is Not Δf, and Its Three Uses02The Chain Rule: Why It Holds, a Worked Check, and the Product Rule03Chain Rule for a Change of Variables: Partials in Polar CoordinatesProblem set0/10Problem set 20/10MIT problem set0/1
Gradients and Constraints
01The Gradient Vector: Why It Is Perpendicular to Level Sets02Tangent Plane to a Surface From the Gradient: The Hyperboloid03Directional Derivatives and the Direction of Steepest AscentProblem set0/10Problem set 20/10MIT problem set0/2
01Lagrange Multipliers: Tangent Level Curves and ∇f = λ∇g02Solving the Lagrange Equations, and Why the Method Works03The Least-Area Gold Pyramid: Its Top Sits Over the IncenterProblem set0/10Problem set 20/10MIT problem set0/1
01Implicit Partial Derivatives: Differentiate the Constraint02Which Variable Is Held Constant? Subscript Notation03A Constrained Rate Three Ways: Differentials vs Chain RuleProblem set0/10Problem set 20/10MIT problem set0/3
Multiple Integrals
01The Heat Equation: A First Partial Differential Equation02Double Integrals: Volume Under a Surface by Slicing03Iterated Integrals Over a Square and a Quarter Disk04Exchanging the Order of Integration: Redraw the RegionProblem set0/10Problem set 20/10MIT problem set0/1
01Double Integrals in Polar Coordinates: Why dA = r dr dθ02Area, Mass, Averages and Center of Mass by Double Integrals03Moment of Inertia: Spinning a Disk About Its Center and Its RimProblem set0/10Problem set 20/10MIT problem set0/3

The Second Derivative Test: Classifying by the Sign of AC − B²

Why do the three second partials A, B, C settle the type of a critical point, and when does AC − B² = 0 leave you stuck?


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Your summary note

    1. 1

      4ac−b24ac - b^24ac−b2 as minus the discriminant

      Rewrite w=ax2+bxy+cy2w = ax^2 + bxy + cy^2w=ax2+bxy+cy2 as y2[a(xy)2+bxy+c]y^2\left[a\left(\frac{x}{y}\right)^2 + b\frac{x}{y} + c\right]y2[a(yx​)2+byx​+c] and record which sign of b2−4acb^2 - 4acb2−4ac gives a saddle and which gives a minimum or maximum.

    2. 2

      The second derivative test with AAA, BBB, CCC

      Define A=fxxA = f_{xx}A=fxx​, B=fxyB = f_{xy}B=fxy​, C=fyyC = f_{yy}C=fyy​ at the critical point, note fxy=fyxf_{xy} = f_{yx}fxy​=fyx​, and list the four cases of AC−B2AC - B^2AC−B2 with their conclusions, including the inconclusive one.

    3. 3

      Reduction to the quadratic case by Taylor approximation

      Write Δf\Delta fΔf to second order, drop the linear terms at the critical point, and match a=A2a = \frac{A}{2}a=2A​, b=Bb = Bb=B, c=C2c = \frac{C}{2}c=2C​ to turn 4ac−b24ac - b^24ac−b2 into AC−B2AC - B^2AC−B2.

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