Why must two equal masses always fly apart at exactly 90 degrees after an elastic collision, and can one dot product prove it?
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Perpendicular outgoing velocities for equal masses
Divide momentum conservation by for , dot it with itself, compare with , and reach .
Testing elasticity from the momentum components alone
Work the collision: solve the two component equations for and , then compare and , both .
The center-of-mass scattering angle
Record the constant boost for a target at rest, and draw the particles approaching and leaving back-to-back with between those directions.