Why is a rolling body's kinetic energy exactly ½MV² plus ½I_cm ω², and what does Chasles's theorem add to that split?
Loading…
Kinetic energy split for any system of particles
Substitute into , expand the dot product, drop the cross term, and record that the result needs no rigidity.
Rigid body:
Write for rotation about an axis through the center of mass and reduce the first sum to .
Rigid-body condition
For two particles, write with the reduced mass , and differentiate the constant squared separation to get the condition.
Chasles's theorem: translation plus rotation
Show the case gives pure translation, and the other case gives perpendicular displacements with , a rotation about the center of mass; note the two-particle argument's limit.