Why is $\cosh x$, not $e^x$, the natural partner for $y'' - y = 0$ once you choose solutions by their starting values?
Loading…
Any independent pair gives the same family
Write , as combinations of , , and show that the combinations of the 's and of the 's are the same collection of functions.
The normalized solutions , at
Write the defining conditions , , , , and check that , satisfy them for .
Deriving and from ,
For , solve the two systems for , to get and , then verify their initial values.
Comparing the standard and normalized pairs
Record which initial value rules out and as or , and write down and .