Why must a gradient field satisfy M_y = N_x, and how does one missing point at the origin let a field pass the test and still fail?
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The test
Write = f_x, then derive = f_{yx} = f_{xy} = M_y$ from the equality of mixed partials.
The converse and its hypothesis
State the converse for a field continuously differentiable on the whole plane, and record , which passes the test away from the origin yet has work \pi$ around the unit circle.
Two worked tests
Apply the test to the rotation field to show it fails, and find the value = 8\langle 4x^2 + axy,\ 3y^2 + 4x^2\rangle$.
The test holds identically, not at a point
Record that = 8x and .